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rising free r ising fr
rising free r ising fr
- 2022-03-17 00:59:15下载
- 积分:1
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软件设计文档国家标准
软件设计文档国家标准-包括有软件需求分析说明,可行性分析,开发计划,设计说明等十五个部分的内容-software design documentation national standards-including software requirements analysis shows, feasibility analysis, development plan Design notes, etc. 15 part of the contents
- 2023-08-24 08:50:03下载
- 积分:1
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TMS320C54x DSP
Functional Overview
TMS320C54x DSP
Functional Overview
- 2022-02-10 09:44:00下载
- 积分:1
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对当前很火的网络电话的分析,分析internet peer to peer telephony protocol...
对当前很火的网络电话的分析,分析internet peer to peer telephony protocol-fire right now is the telephone network analysis, peer to peer internet telephony protocol
- 2022-02-03 23:01:05下载
- 积分:1
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LCS Algorithm, this is a c++ code for lcs(Longest Common Subsequence)
LCS算法,这是一个用于LCS(最长公共子序列)的c++代码
- 2023-05-20 02:20:03下载
- 积分:1
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only VHDL
基才VHDL状态机设计的智能交通控制灯
设计 有需要的可以看一下-only VHDL-based state machine design and intelligent traffic control lights need to design can look at the
- 2023-02-02 02:35:03下载
- 积分:1
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doxygen(一个自动从源代码生成文档的工具)的源代码,可以在Win32/Linux/Unix上编译通过。...
doxygen(一个自动从源代码生成文档的工具)的源代码,可以在Win32/Linux/Unix上编译通过。-Doxygen (an automatically generated source code documentation tools) source code can be compiled in Win32/Linux/Unix through.
- 2022-06-16 22:01:36下载
- 积分:1
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SMS sms AT Chinese control instructions detailed documentation
简体中文短信控制说明详细文档
- 2022-01-21 20:27:46下载
- 积分:1
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多方面的文章
一篇关于多目标跟踪的文章,综述了多目标跟踪问题的不同方法及其区别,是学习目标跟踪的好文章
-An article on multi-target tracking in article, an overview of multi-target tracking problem and the distinction between different methods is a good target tracking study article
- 2022-05-10 12:03:59下载
- 积分:1
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还有一个缺陷就是在只知道密文 x 及公钥(n,e)的情况下,只要将 (x^e) mod n 所得余数 s 再不断地循环操作 s = s^e mod n,此运算不...
还有一个缺陷就是在只知道密文 x 及公钥(n,e)的情况下,只要将 (x^e) mod n 所得余数 s 再不断地循环操作 s = s^e mod n,此运算不断地循环 e 次之后,很多情况下都可以循环出原文,只是计算量过余多一些罢了。不过有不少情况下,根本都无须循环 e 次,不过对于1024位的 n 级别来说,e 也是一个相当大的数值,所以循环密文的余数以解得原文是有些不现实。 以上内容仅供参考,如有不实,请予更正-there is a defect in only know that the secret and public key-x (n, e) the circumstances, as long as (x ^ e) mod n from the remaining s to continuously cycle operation s = s ^ e mod n, this constant cycle of Operational e occasion, the very many circumstances can be recycled from the original, but I calculated the volume more than just. There are, however, many instances, simply do not need e cycle times, but for 1024 the level n, e is a very large figure, so secret circle the remainder of the text was obtained in the original is a bit unrealistic. The above is for reference only, if not true, I corrected
- 2022-08-03 02:51:21下载
- 积分:1