usinf pic16c57 to achive copy machine for pic16c65/66(programmer)

DSP2407的CAN通讯例程，调试通过。-DSP2407 the CAN communication routines, debugging through.

可以还源星号密码，是汇编朋友学习的好教材-You can also source an asterisk password, the compilation is good material for a friend to learn

反汇编disasm的源代码 反汇编disasm的源代码-anti-disasm compilation of the source code compilation disasm against the source code of the anti-compilation disasm source code

用DSP实现PN码,用汇编语言编程实现,-with DSP PN code, assembly language programming,

用于实现人机和人人对话的汇编程序，用户可以利用它实现五子棋的游戏-Used to implement human-computer and a compilation of all the dialogue process, users can use it to achieve the backgammon game

这是本人编写的万年历,内容简洁,只有三十条代码左右.-This is my prepared by the calendar, concise, only about 30 code.

dac7512,mcp3204应用 -dac7512, mcp3204 application dac7512, mcp3204 Application

12232液晶的测试驱动程序，在12232通过at89s51显示12232的液晶测试程序。用汇编写成测试可以使用-12232 LCD test driver, in the 12232 through 12232 of the liquid crystal display AT89S51 test procedure. With the compilation of written test can be used

DEbug 关于制作瑞星杀毒软件密钥盘的源码 MOV BX,200 ;内存基址(0面) MOV DH,00 ;磁头号00 MOV DL,00 ;驱动器号00(A盘) MOV CX,4F01 ;4F(即79)号磁道01号扇区 即(CH=4F CL=01) MOV AH,05 ;格式化磁道 MOV AL,09 ;连续读取9个扇区 INT 13 ;调用13号中断 INT 3 MOV BX,300 ;内存基址(1面) MOV DH,01 ;磁头号01 MOV DL,00 ;驱动器号00(A盘) MOV CX,4F01 ;4F(即79)号磁道01号扇区 即(CH=4F CL=01) MOV AH,05 ;格式化磁道 MOV AL,09 ;连续读取9个扇区 INT 13 ;调用13号中断 INT 20 ;返回dos 初学汇编，请各位多多指教！-Debug on the production of Rising antivirus software key source disk MOV BX, 200 memory base address (0 face) MOV DH, 00 head No. 00 MOV DL, 00 drive No. 00 (A disk) MOV CX, 4F01 4F (ie 79) of track that is on the 1st sector (CH = 4F CL = 01) MOV AH, 05 formatted track MOV AL, 09 consecutive read 9 sector INT 13 call on the 13th interruption INT 3 MOV BX, 300 memory base address (1 side) MOV DH, 01 head No. 01 MOV DL, 00 drive No. 00 (A disk) MOV CX, 4F01 4F (ie 79) of track that is on the 1st sector (CH = 4F CL = 01) MOV AH, 05 formatted track MOV AL, 09 consecutive read 9 sector INT 13 call on the 13th

编写函数int index返回字符t在字条串s中出现的最左边的位置，如果在s中没有与t匹配的子串，不返回-1-function int index prepared to return to the characters not string"s note appeared in the leftmost position, If s and t is not matched substring, not to return-1