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ff LKDSFNV_C_dlkfausdf_buzhidaoff LKDSFNV_C_dlkfausdf_buzhidaoff LKDSFNV_C_dlkfa...
89C51与字符型液晶模块16x2联接的C语言程序 89C51与字符型液晶模块16x2联接的C语言程序 -ff LKDSFNV_C_dlkfausdf_buzhidaoff LKDSFNV_C_dlkfausdf_buzhidaoff LKDSFNV_C_dlkfausdf_buzhidaoff LKDSFNV_C_dlkfausdf_buzhidaoff LKDSFNV_C_dlkfausdf_buzhidao
- 2022-07-09 02:33:21下载
- 积分:1
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这里实现跑马灯的方法是,依次灭掉前一个灯和点亮后一个灯,再延时一会,不断循环,就可以看到跑马灯的效果了。
请在编译后,进入仿真,点全速运行看结果...
这里实现跑马灯的方法是,依次灭掉前一个灯和点亮后一个灯,再延时一会,不断循环,就可以看到跑马灯的效果了。
请在编译后,进入仿真,点全速运行看结果-Marquee realize here the approach is to eliminate the former followed by a light and lit a lamp post, and then one will be delayed, and constantly cycle, you can see the effect of the Marquee. Please compiled into the simulation, watch the results point to run at full speed
- 2022-02-05 23:53:18下载
- 积分:1
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SampleAndroid : the base sample project for android
SampleAndroid : the base sample project for android
- 2022-03-11 07:07:54下载
- 积分:1
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瑞佑RA880X系列微控制器的官方驱动程序及DEMO例程,稍加修改就可移植。花了点精力下载到的。...
瑞佑RA880X系列微控制器的官方驱动程序及DEMO例程,稍加修改就可移植。花了点精力下载到的。-RA880X series瑞佑official microcontroller driver routines and DEMO, a little modification can be transplant. Point of energy spent to download.
- 2022-02-05 08:36:08下载
- 积分:1
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galib面向对象C++库,来自麻省理工大学的
galib面向对象C++库,来自麻省理工大学的-galib object-oriented C library, from the University of Massachusetts
- 2022-05-23 05:35:19下载
- 积分:1
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二重积分 Guass―L高精度求积计算,精度高,速度快
二重积分 Guass―L高精度求积计算,精度高,速度快-double integral Guass-L for the calculation of high-precision, high accuracy and speed
- 2022-02-06 05:58:55下载
- 积分:1
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问题描述:
一杯沸水冷却,圆柱体模型,底面半径0.05m,高0.1m,周围温度20度,初始水温100度
方程是四维输运方程(常数a^2=k/(c*...
问题描述:
一杯沸水冷却,圆柱体模型,底面半径0.05m,高0.1m,周围温度20度,初始水温100度
方程是四维输运方程(常数a^2=k/(c*p),k是热传导系数0.6006焦/(米*秒*度))
初始条件:t=0时水等于100度
边界条件:1.上下壁都是自由冷却,第三类边界条件,周围温度保持在20度(H=k/h,h取1)
2.杯壁绝热,第二类边界条件
图形显示格式,取过圆柱轴的截面温度变化将其做成动画.
-Problem description : a cup of boiling water cooling cylinder model, the bottom radius of 0.05m, 0.1m high. temperature around 20 degrees, initial temperature of 100 degrees equation is four-dimensional equations (a constant ^ 2 = k/(c* p), k is the thermal conductivity coefficient of 0.6006 Coke/(m** seconds degrees)) initial conditions : t = 0 to 100 degree water boundary conditions : 1. upper and lower walls are free cooling, the third boundary conditions, maintain the temperature around 20 degrees (H = k/h, h for 1) 2. Beibi insulation, The second category boundary conditions graphics format, cylindrical shaft for the cross section of its temperature changes caused animation.
- 2022-05-12 17:55:03下载
- 积分:1
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做为一个例子,它是一个很好的学习FLASHMX的例子
做为一个例子,它是一个很好的学习FLASHMX的例子-as an example, it is a very good example of learning FLASHMX
- 2022-01-21 04:42:51下载
- 积分:1
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使用LabVIEW实现Modbus CRC计算
利用LabVIEW语言实现MODBUS协议中CRC校验-use LabVIEW to accomplish the CRC calculate in MODBUS
- 2022-02-25 18:32:08下载
- 积分:1
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Visual Studio 2005
几个网站控件的使用例子
Visual Studio 2005
几个网站控件的使用例子-Visual Studio 2005 website several examples of the use of control
- 2022-02-06 22:49:10下载
- 积分:1