本人学习PHP的摘要，都是一些看过的书的重点

Learning Python, Third Edition

网上购物.实现一个网上购物的程序.服务器通过Personal Web Server服务器软件在Internet上发布网上订购自行车的主业,用户可以通过该主页填写定单并发送给服务器,服务器获取用户定单并反馈给用户一个确认消息.-online shopping. Achieving an online shopping process. Personal Web servers Ser ver server software released on the Internet online ordering the main bicycle industry, The user can fill in the Home orders and send server, Server users access to orders and feedback to the user confirming the news.

电机转速控制的实验指导，有原理图和实验说明可以参考，-Motor speed control experiments guidance and experimental schematic description can refer to,

usb-数据流的中文详细介绍, 需要的请下-usb-data stream details in Chinese, the needs of call on the next

公积金监管系统Com中间件,是新疆公积金监管系统的客户端软件，采用了webservice+Dcom-provident fund monitoring system Com middleware, Xinjiang provident fund monitoring system client software, using a webservice Dcom

ICAD的开发全集，很好的东西，希望大家赶快下载！-Complete the development of ICAD, a very good thing, I hope everyone downloads as soon as possible!

还有一个缺陷就是在只知道密文 x 及公钥（n,e）的情况下，只要将 (x^e) mod n 所得余数 s 再不断地循环操作 s = s^e mod n，此运算不断地循环 e 次之后，很多情况下都可以循环出原文，只是计算量过余多一些罢了。不过有不少情况下，根本都无须循环 e 次，不过对于1024位的 n 级别来说，e 也是一个相当大的数值，所以循环密文的余数以解得原文是有些不现实。 以上内容仅供参考，如有不实，请予更正-there is a defect in only know that the secret and public key-x (n, e) the circumstances, as long as (x ^ e) mod n from the remaining s to continuously cycle operation s = s ^ e mod n, this constant cycle of Operational e occasion, the very many circumstances can be recycled from the original, but I calculated the volume more than just. There are, however, many instances, simply do not need e cycle times, but for 1024 the level n, e is a very large figure, so secret circle the remainder of the text was obtained in the original is a bit unrealistic. The above is for reference only, if not true, I corrected

lattice 的CPLD 资料 lattice 的CPLD 资料-lattice of the CPLD data

华为的编程开发规范与案例,了解华为的开发规范很有帮助-Huawei programming norms and precedents understanding of the development of standardized Huawei helpful

PTZ控制协议详细信息，包括pelcou d、pelcou p、yaan。