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optional exercise4答案，比较详细-optional exercise4

一个简单的C语言编译器-a simple C language compiler

简单的词法分析，可以识别关键字错误，识别无效符号等等，通用！-Simple lexical analysis to identify the wrong keywords, identify invalid symbols and so on, General!

采用递归下降子程序书写的编译原理关于“PL0文法”的编译器，支持词法分析语法分析目标代码生成-grammar

本程序用于语法分析-procedures for the analysis of syntax

CFront1.0的源代码,第一代C++编译器的思想-CFront1.0 the source code, the first generation of C++ compiler of thinking ...

Osprey源代码,绝对值得一看,Osprey权威资源代码-Osprey source code is absolutely worth a visit, Osprey authoritative source code

一个简化的编译器，出自美国编译领域的大师劳顿之手，在UNIX/LINUX环境下实现，适合初学者进行分析-a simplified compiler, the United States compiled from the master Lawton hand, UNIX/LINUX environment realized, the analysis for beginners

AutoCAD 2005中文版建筑制图新概念百例-源代码 -AutoCAD 2005 English edition of the new concept of one hundred cases of Architectural Drawing- 2005 Chinese version of the source code for the new concept of one hundred cases of Architectural Drawing- the source code for

C语言词法分析器 by wpc_LK 这是一个简单的词法分析器，不能避免的存在错误请大家指出予以纠正，谢谢！ 示例语句 include int main{ int a=3,b=4,c if((a+b)==7)c=1 else c=0 return 0 } 输入 exit 退出程序。-C language lexical analyzer by wpc_LK This is a simple lexical analyzer can t avoid that there re some errors here,please correct, thank you! for exzample: include int main{ int a=3,b=4,c if((a+b)==7)c=1 else c=0 return 0 } input exit quit the program.