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Beyond the C++ Standard Library An Introduction to Boost
Beyond the C++ Standard Library An Introduction to Boost
- 2023-06-24 18:50:04下载
- 积分:1
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WINDOWS窗口设计文档,还是很不错的,呵呵,大家可以
WINDOWS窗口设计文档,还是很不错的,呵呵,大家可以-WINDOWS window design documents, or very good, huh, huh, we can
- 2022-05-22 22:27:31下载
- 积分:1
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用户识别系统 简单的使用类继承完成,使用到文件流!
用户识别系统 简单的使用类继承完成,使用到文件流!-user identification system using a simple succession category completed, the use of the document flow!
- 2022-11-08 18:45:02下载
- 积分:1
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在不改变系统记事本源代码的前提下,为系统记事本增添统计计数功能。...
在不改变系统记事本源代码的前提下,为系统记事本增添统计计数功能。-Notepad without changing the system under the premise of origin code for the system to add statistical counting function Notepad.
- 2022-02-05 21:25:43下载
- 积分:1
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LED闪烁端口下载它的AVR沙头角500盒
led blink port a download it avr stk 500 kit
- 2022-01-31 21:57:04下载
- 积分:1
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有关异常程序的应用和实现,如何抛出异常,继续处理程序。
有关异常程序的应用和实现,如何抛出异常,继续处理程序。-The application and achievement about exception programme,how to throw out exception,and continue to handle programme.
- 2022-04-12 06:45:08下载
- 积分:1
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Please tree G, and with the right Vertices adjacency matrix, as well as for two...
请将树G的顶点数和带权邻接矩阵以及待求两点输入进input.txt。如果两点间无边连接,则
用大数65535来表示。-Please tree G, and with the right Vertices adjacency matrix, as well as for two points to be input into input.txt. If between two points limitless connectivity, is used to express large numbers 65,535.
- 2022-09-08 06:45:02下载
- 积分:1
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AIC bands in accordance with statutory order recursive algorithm procedures in a...
AIC频段按照法定顺序递归算法程序按照顺序递归算法进行了估计,然后利用下面的方程确定残差方差的估计值:从AIC的计算结果类型:找到模型结果中最小的AIC(阶数和参数)是估计模型。源代码:aic2.dsw。结果存储在:数据.txt. 通过输出数据,我们可以看出当k1=5时AIC的最小值。因此,最终确定顺序为5,检查结果为参数为:-1.18394,0.813938,-0.518174,0.348744,-0.116818,1.07998,-0.74386,0.475444,-0.253022,0.122781,以确定最小AIC值:AIC=--8981.58,以5:00为顺序出现。
- 2023-05-08 21:35:03下载
- 积分:1
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关于调用数据库的程序!
关于调用数据库的程序!-database called on the procedure!
- 2022-02-20 19:12:16下载
- 积分:1
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非侵入式的测量骨头的厚度,利用超声导波的方法。
非侵入式的测量骨头的厚度,利用超声导波的方法。-Noninvasive assessment of human jawbone using ultrasonic guided waves
- 2022-08-21 14:43:01下载
- 积分:1