我玩的一个游戏嘛

我在项目开发过程中，自己开发的一个日志工具，使用c++语言开发。使用单线程，不阻塞主线程。日志存放在事先分配好的多条队列中，运行期间可检测队列情况而释放或者增加缓冲区。最大发挥日志的速度。当然也有问题，主线程崩了的话，日志线程也会崩的。

,COM通讯，简单的调用MSCOMM控件.错误之处还请见谅。嘿嘿哈哈 -rarrarrarrarrarrarrarrarrarrarrarrarrarrarrarrarrarrarrarrarrarrarrarrarrarrarrarrarrar

一个画图小软件，用来熟悉C++的OOP机制，初学者适用-A small drawing software, to become familiar with C++, OOP mechanism for beginners

C#语言实现的字符串比较，适合初学者对.net环境和C#的学习-C# language implementation of string comparison, suitable for beginners. Net learning environment and C#

add4 verilog code -add4 Verilog code

8253fenpinjijishuqishiyansuoshiyongdehuibianyuandaima -8253fenpinjijishuqishiyansuoshiyongd ehuibianyuandaima

C++常用算法程序集 -C++常用算法程序集

二维无网格伽辽金法简单例子程序-2D-EFGM simple example Act procedures

不错的股票实时曲线图，javaApplet方式实现。效果不错。-Good stock in real-time graph, javaApplet way. Good results.

for： Root of a Polynomial --- --- --- --- -- Time Limit: 1 Second Memory Limit: 32768 KB -------------------------------------------------------------------------------- A polynomial of degree n has the common form as . Your task is to write a function to find a root of a given polynomial in a given interval. Format of function double Polynomial_Root(int n, double c[], double a, double b, double EPS) where int n is the degree of the polynomial double c[] is an array of n +1 coefficients , , ..., , and of the given polynomial double a and b are the two end-points of the given interval and double EPS is the accuracy of the root. The function must return the root. Note: It is guaranteed that a unique real number r exists in the given interval such that p(r) = 0. -for: Root of a Polynomial---------------------- Time Limit: 1 Second Memory Limit: 32768 KB-------------------------------------------------------------------------------- A polynomi