数据挖掘领域经典：数据挖掘中10个最挑战的问题

从16x16字库中读内容的小程序,使用visual C++开发。仅供初学者使用-from 16x16 character read as a small, the use of visual C development. Only beginners

自己做的一些小编程，里面很多基础知识！堆新手又一定帮助！-Themselves to do some small programming, which a lot of basic knowledge! Definitely help stack novice!

数据结构：带括号的算术表达式求值。能完成一位数的带括号的算术表达式的运算，结果可以为多位数。用栈实现中缀表达式和后缀表达式的转换。-data structure : the bracketed arithmetic expression is evaluated. Complete with a number of brackets arithmetic expression Operational results for the multi-digit number. With Stack Implementation grade expression and suffixes expression change.

一个使用VC.NET代码写的MP3媒体播放器，有兴趣的朋友可以下载研究一下-a mp3 player programed by vc.net,anyone who have interest in it can download and research

遗传算法及绘图VC程序包

该程序是个文字编辑器控件，可以和CEdit使用来过滤输入的文字。-A edit box control that can mask/filt the input in CEdit.

可以把VC7.0的文件转换成VC6.0的文件，非常好用-Convert project file of VC7.0 to VC6.0

DFA的“语言”是这个DFA接受的所有的串的集合。假设a1a2…an是输入符号序列，让这个DFA从初始状态q0开始运行。查询转移函数δ，比如说δ(q0,a1)=q1，以找出DFA在处理了第一个输入符号a1之后进入的状态。处理下一个输入符号a2，求δ(q1,a2)的值，假设这个状态是q2。以这种方式继续下去，找出状态q3,q4,…,qn，使得对每个i，δ(qi-1,ai)=qi。如果qn属于F，则接受输入a1a2…an，否则就“拒绝”。-DFA" s " language" is the DFA to accept all of the string collection. A1a2 ... an assumption is an input symbol sequence, so that the DFA into operation from the initial state q0. Look transfer function δ, say δ (q0, a1) = q1, in order to identify the DFA in dealing with the first input into the state after the symbol a1. To the next input symbol a2, seeking δ (q1, a2) values, assuming that this state is q2. Continue in this way to find out the state q3, q4, ..., qn, making for every i, δ (qi-1, ai) = qi. If qn belongs to F, then accept the input a1a2 ... an, otherwise, " refuse."

刚学JAVA的时候老师布置的作业,一个简单的小JAVA程序,关于学生信息的.主要目的是接触JAVA.-just learning the layout of the teachers work, a simple small Java procedures, information on the students. The main purpose is to contact JAVA.

VC的托盘程序,可供参考-VC procedure trays, for example,