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Graph adjacency list, stack, queue, such as code storage structure.
图的邻接表、栈、队列等存储结构代码实现。-Graph adjacency list, stack, queue, such as code storage structure.
- 2023-04-30 15:35:03下载
- 积分:1
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After running the program without any problems, can be used to solve the urgent...
该程序经过运行,无任何问题,可用于解决紧急搜索算法求解车辆路线问题-After running the program without any problems, can be used to solve the urgent search algorithm to solve Vehicle Routing Problem
- 2022-07-19 21:21:38下载
- 积分:1
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being the largest segmentation method tagging source
正向最大切分法+词性标注源码-being the largest segmentation method tagging source
- 2022-03-30 04:18:40下载
- 积分:1
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NTFS格式下将文件目录看作符号进行连接.相当于对一个路径可用别名访问....
NTFS格式下将文件目录看作符号进行连接.相当于对一个路径可用别名访问.-NTFS format file directory as symbols connected. The equivalent of a visit Alias path available.
- 2022-07-13 22:14:12下载
- 积分:1
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该请求页式存储管理方案采用先进先出(FIFO)页面淘汰算法
1.登录的账号:yangmingyuan
登录的密码:123456
2.物理块数由用户自己输入大小可以随意选定。
3. 在输入请求的页面时候,请依次输入页面号并且页面号之间要用空格
隔开,最后不要有空格等其他非数字字符结束。
4.然后单击输入按钮将页面号输入,弹出确定的对话框单击确定,最后单
击开始FIFO按钮开始执行调页算法。在调页过程框中观察具体的调页顺序
及调页过程,并且可以观察到缺页数和缺页率的大小。
5.最后单击退出按钮退出该系统。
- 2023-07-13 15:15:04下载
- 积分:1
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vivi
vivi -vivi 1111111111111111111111111111111111111111111
- 2022-02-01 02:54:08下载
- 积分:1
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Samsung s3c2440NBOOT, USB communications,
三星s3c2440NBOOT,USB通信,-Samsung s3c2440NBOOT, USB communications,
- 2022-04-11 20:34:09下载
- 积分:1
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C++标准程式库
C++标准程式库-C standard library programs
- 2022-06-17 05:23:04下载
- 积分:1
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动态规划
动态规划----矩阵连乘问题 动态规划法是解决问题的一种方法。它不规定为了得到结果需如何将问题划分为子问题的固定方法,而是按不同输入给出问题的具体实例的子问题划分方法,然后再进行运算、解答问题。 矩阵连乘问题的主要思想如下: 1)设置大小为连乘个数的方阵 2)主对角线上方各元素Di,j(ij)记录获得该最小工作量矩阵分组的第一组的最后一个矩阵的序列号 最后通过下方元素可知最终结果的分组方式。-dynamic programming matrix continually multiply-dynamic programming problem is a problem-solving method. It does not require the results need to be how to divide the problems of the sub- problems fixed, but different input given by the specific example of the problem partition method, and then calculate, and answer questions. Matrix continually multiply the main idea is as follows : 1) the installation of the size of continually multiply the number phalanx 2) above the main diagonal elements Di, j (ilt; J) Matrix Mi continually multiply to the smallest workload 3) below elements Di, j (IGT; J) the record was the smallest workload of a matrix of the first group of a matrix of the final sequence, followed by the final element of the final results of the
- 2022-06-17 10:27:59下载
- 积分:1
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C/C++教程,源程序实例,小而精好实用
C/C++教程,源程序实例,小而精好实用-C/C tutorial, example source, a small but good practical
- 2022-03-19 23:21:42下载
- 积分:1