用C++Builder控制众为兴ADT8940 运动控制卡，里面做成了一个控制类...

3D坐标系演示 使用Visual studio打开,C#开发，简单易懂，开用于新手学习3D模型

钱能编的《C++教程》及课后答案，及源代码-Money will be allocated to the

哈夫曼树编码,利用哈夫曼树算法实现对数据的压缩-Compress data by Huffman coding

flash饼图投票系统单用户版 v2.0.rar-flash pie voting system single-user version v2.0.rar

增加了用户设置的智能指针，用户可以设置该智能指针为非传统的指针。-An increase of user settings smart pointer, the user can set the smart pointer for non-traditional indicators.

一个用VC开发的windows记事本程序,并提供听音乐等windows记事本的额外功能-a VC development of the windows Notepad procedures, and listening to music for the notebook windows of the additional functions

Net代码20个,需要我们学习!-20, we need to learn!

Programming Fundamental 课程的Assignment 2 ， 制作一份 用java 编写的Wumpus小游戏，界面优良，只是这是一份一开始显示游戏要素的版本，如若需要，可以稍作修改

database management system

生命游戏，规则： 1、一个细胞周围八个格存活2～3个细胞，则下一时代次此细胞依然存活 2、如果某个格周围八个格存活三个细胞，则下一时代该格能创生一个细胞 3、如果一个细胞周围8格存活细胞数为1个或1个一下，则下一世代该细胞因孤独而死 4.如果一个细胞周围8格存活细胞数为4个或4个以上，则下一世代该细胞因生存空间拥挤而死-Game of Life rules: 1, a cell survival of the surrounding eight grid cells 2 ~ 3 months, then the next times at 2 this cell is still viable, if a grid around the eight cell survival of three cells, then the next era of the grid to creation of a cell 3, around 8, if a cell survival of cells for cell 1 or a click, then the next generation of the cells die because of loneliness 4. If a cell survival of cells in the surrounding 8 cells for 4 or 4 or more, then the next generation of the cells died due to crowded living space