-
Plam 编程非常权威的书,包括UI,网络等Plam系统的各个方面.
Plam 编程非常权威的书,包括UI,网络等Plam系统的各个方面.-Plam programming very authoritative book, including the UI, network Plam system in all its aspects.
- 2022-12-30 02:40:03下载
- 积分:1
-
74FCT164245 device on the descriptive information, I take it from abroad found o...
这是一个关于74FCT164245器件的说明资料,是我从国外的网站上找到的.-74FCT164245 device on the descriptive information, I take it from abroad found on the website.
- 2022-03-26 19:33:09下载
- 积分:1
-
《微带天线理论与工程》书籍学习微带天线的好材料
《微带天线理论与工程》书籍学习微带天线的好材料-Microstrip antenna theory and engineering
- 2022-03-16 12:02:09下载
- 积分:1
-
and eat a rather interesting and the book, and eat a rather intere sting and the...
吃一本很有趣的书,吃一本很有趣的书
- 2022-07-09 12:30:04下载
- 积分:1
-
procedures, based on the comparison of things, we all see Pakistan attached grea...
java的范例程序,比较基础的的一些东西,大家自己去看看巴风大所附-procedures, based on the comparison of things, we all see Pakistan attached great wind.
- 2022-01-26 04:13:57下载
- 积分:1
-
GB software design standards document
国标软件设计标准文档-GB software design standards document
- 2023-06-18 22:50:03下载
- 积分:1
-
lq10D367的英文资料,非常详细的介绍了该屏的时序。
lq10D367的英文资料,非常详细的介绍了该屏的时序。-English lq10D367 information, very detailed introduction of the timing screens.
- 2022-04-12 06:07:31下载
- 积分:1
-
HUMBLE LITTLE RUBY BOOK
This is a really good book for starters who want to learn ruby well.
An up to date book on Ruby programming, written in a style described as "a beautiful display of pragmatically chunky bacon,
wrapped in a nutshell." Or something like that.
Mr. Neighborly"s Humble Little Ruby Book covers the Ruby language from the very basics of using puts to put naughty
phrases on the screen all the way to serving up your favorite web page from WEBrick or connecting to your favorite web
service. Written in a conversational narrative rather than like a dry reference book, Mr. Neighborly"s Humble Little Ruby
Book is an easy to read, easy to follow guide to all thin
- 2022-03-22 20:41:41下载
- 积分:1
-
传教士与野人问题我们分两种情况考虑。先考虑船在左岸的情况。如果不考虑限制条件,也就是说,船一次可以将三人从左岸运到右岸,然后再有一个人将船送回来。这样,船一个来...
传教士与野人问题我们分两种情况考虑。先考虑船在左岸的情况。如果不考虑限制条件,也就是说,船一次可以将三人从左岸运到右岸,然后再有一个人将船送回来。这样,船一个来回可以运过河2人,而船仍然在左岸。而最后剩下的三个人,则可以一次将他们全部从左岸运到右岸。所以,在不考虑限制条件的情况下,也至少需要摆渡[(M+N-3)/2]*2+1次。其中分子上的"-3"表示剩下三个留待最后一次运过去。除以"2"是因为一个来回可以运过去2人,需要[(M+N-3)/2]个来回,而"来回"数不能是小数,需要向上取整,这个用符号[ ]表示。而乘以"2"是因为一个来回相当于两次摆渡,所以要乘以2。而最后的"+1",则表示将剩下的3个运过去,需要一次摆渡。-M-C products
- 2022-03-03 01:31:52下载
- 积分:1
-
VC技术内幕第五版
VC技术内幕第五版-technology VC Insider Awards
- 2023-07-09 20:05:03下载
- 积分:1