现有的信号：x（n）= cos（n / 4）cos（2×N / 3）和数字滤波器设计…

现有一个信号：x(n)=1+cos(π*n/4)+ cos(2*π*n/3)设计及各种数字滤波器以达下列目的： 低通滤波器，滤除cos(2*π*n/3) 的成分，即想保留的成分为1+cos(π*n/4) 高通滤波器，滤除1+cos(π*n/4) 的成分，即想保留的成分为cos(2*π*n/3) 带通滤波器，滤除1+cos(2*π*n/3) 的成分，即想保留的成分为cos(π*n/4) 带阻滤波器，滤除cos(π*n/4) 的成分，即想保留的成分为1+cos(2*π*n/3) 1. 用MATLAB命令butterord求除滤波器的阶数,用命令butter设计各滤波器；画出滤波器幅度和相频相应 取各滤波器的系统函数H(z)。 -an existing signal : x (n) = a cos (* n/4) cos (2** n/3) design and digital filter to achieve the following objectives : low-pass filter, filter cos (2** n/3) the ingredients that want to retain an element of a cos (* n/4) high-pass filter, a filter cos (* n/4) components, namely to retain the element of cos (2** n/3) band-pass filter , a filter cos (2** n/3) components, namely to retain the element of cos (* n/4) band stop filter, the filter cos (* n/4) components, namely to retain the ingredients for a cos ( 2** n/3) 1. MATLAB order butterord except for the band Filter, using the order of the filter design butter; paint Filter magnitude and phase frequency of th