Pipelined Implementation of Baseline JPEG Encoder

一个命名实体识别工具，是Mallet开放源码项目的一部分，可用于识别文本中的人名、地名等信息-a named entity recognition tools, Mallet OSS part of the project, Text can be used to identify the names, places and other information

图形模式下的汉字显示-graphics mode display of Chinese characters

具有三级索引词库结构的中文分词方法研究 -Three-tier structure with a thesaurus of indexing Chinese word segmentation method

将中文内容，入姓名，商品名等等自动生成拼音字母开头的拼音码的函数例子。-The Chinese-language content, into the name, trade names, and so automatically generated phonetic alphabet at the beginning of the function of the phonetic code examples.

用VB6.0开发的中文词频统计软件，可在word文档中自动找出所有的词语，并从按照词频高低排序。附测试文档。-Using VB6.0 to develop the Chinese word frequency statistics software, word document can automatically identify all of the words, and sorted according to high and low frequency. Attached to the test document.

中文分词演示，海量科技的中文分词的词库，第一次做这样的技术，希望和大家交流-Chinese word segmentation demonstration, mass technology thesaurus of Chinese word segmentation, the first to do this kind of technology, hopes and U.S. exchange

一个以前写的东东，使用idhttp提交到国外顶级翻译网站实行翻译功能，翻译准确率比金山快译2005的全文翻译要准确多了，至少我是这样认为的。韩文翻译有编码问题，还请高手改改，改好记得要给我传份。简繁互译问题今天整理的时候才发现有问题，服务器不能准确的进行简繁互译，其他语言换繁体都没有问题，不是程序本身问题-before writing a saucepan, use idhttp submitted to the translation of the top foreign websites to carry out the translation function, accurate translation Jinshan faster rate than 2,005 translated to the translation accurate, at least I think so. Korean translation of a coding problem, and also 19:56 change it, it is better to remember to give it to me- in. Babel Translation problems sorted out today when problems are detected, the server is not an accurate translation for Babel, other languages are not traditional for the problem, not the problem itself

动态规划解决LCS-dynamic programming solution LCS

用Doolittle方法求解此方程组； 1．先由U[1][i]=a[1][i] 求的U的第一行，在根据L[i][1]=a[i][1]/U[1][1] 求的L的第一列；2..然后根据公式求得U，L其他的值； 3 回带求解得到X -Try using this method to solve equations; 1. First U [1] [i] = a [1] [i] for the U in the first line, in accordance with L [i] [1] = a [i] [1]/U [1] [1] L for the first out; 2 .. according to equation U, L other values; three to be solved with X

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