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AjaxSample
说明: 一个基于C#的AJAX的源代码以及DEMO项目。AJAX采用XMLHTTP + JS 实现的无刷新页面的技术,典型应用有 Google Map等。(Source code of c sharp based on AJAX, and a demo project with it. The implement of AJAX is using XMLHTTP and JavaScript without refresh web pages, specific application with AJAX is Google Map and so on)
- 2005-09-05 10:23:17下载
- 积分:1
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weifen
微分方程模型代码,很多时候差分格式的重写(the function as is code)
- 2011-12-23 22:38:44下载
- 积分:1
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sensorloss
DSP TMS320F28335 无位置传感器直流无刷电机控制(DSP TMS320F28335 BLDC)
- 2018-05-08 11:36:15下载
- 积分:1
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15年电赛控制类——风力摆
风力摆是一种通过风机作为唯一动力驱动的装置,深入研究该系统对空间飞行器、四旋翼无人机的运动状态和卫星姿态控制具有重大意义。(Wind pendulum is a device driven by wind turbine as the only power. It is of great significance to study the motion state of space vehicle, quad-rotor UAV and satellite attitude control.)
- 2020-06-19 10:40:02下载
- 积分:1
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vc-DAO-data
说明: 这是个数据库相关的源代码,希望对大家有帮助,连接DAO数据库,希望大家多多支持(This is a database-related source code, in the hope that we help to connect DAO database, hope that we can support)
- 2008-10-14 00:53:22下载
- 积分:1
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getpes
可以将TS流中的PES信息内的PTS位置标定(TS stream can be within the PTS PES position calibration information)
- 2013-10-21 12:31:06下载
- 积分:1
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3通道120°相位差方波
说明: 0.2通道180°相位差方波,3通道120°相位差方波,4通道90°相位差方波
1.试验平台stm32f103c8t6
2.2通道用定时器3的1、2通道;3通道用定时器3的1、2、3通道;4通道用定时器3的1、2、3、4通道;
3.实现方法,周期和占空比用捕获通道中断反复修改捕获值来实现
4.相位差采用定时器的生效同步规则来实现(下一次更新时间生效)(0.2 channel 180 degree phase difference square wave, 3 channel 120 degree phase difference square wave and 4 channel 90 degree phase difference square wave
1. Test platform stm32f103c8t6
2.2 channels use 1, 2 channels of timer 3; 3 channels use 1, 2, 3 channels of timer 3; 4 channels use 1, 2, 3, 4 channels of timer 3;
3. Realization method, period and duty cycle are realized by repeatedly modifying capture value with capture channel interrupt
4. The phase difference is realized by the effective synchronization rule of the timer (the next update time takes effect))
- 2020-06-24 06:00:02下载
- 积分:1
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josephus
通过c语言数组算法解决josephus问题,m个人围成一圈,从第一个小孩开始顺时针方向每数到第n个小孩时这个小孩离开,最后剩下的小孩是胜利者。求第几个小孩为胜利者(C language array algorithm to solve the Josephus problem, m individual circle, from the first child began to count clockwise every n children, the child left, and finally the remaining child is the winner. A few kids for victory)
- 2017-11-12 10:30:06下载
- 积分:1
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Lwip(socketio)
【实例简介】
- 2021-09-07 00:31:05下载
- 积分:1
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EnvironmentalReverb
A sound generated within a room travels in many directions.
- 2014-10-03 13:34:07下载
- 积分:1