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一个关于多线程实例的程序
一个关于多线程实例的程序-program about multi thread
- 2022-07-02 20:05:13下载
- 积分:1
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ojective C for Iphone example code.
ojective C for Iphone example code.iphone 开发代码.-ojective C for Iphone example code.
- 2023-04-03 01:30:03下载
- 积分:1
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dll 动态加载类的简单例子. 类中只有两个虚函数:Create() 和 Destroy()....
dll 动态加载类的简单例子. 类中只有两个虚函数:Create() 和 Destroy().-class loaded dynamically in dll.
Only 2 virtual functions are important in this class: Create() and Destroy(). Create() function returns TRUE if the DLL is loaded correctly and an instance handle obtained. Destroy() will unload the DLL from process memory.
- 2022-01-30 18:14:26下载
- 积分:1
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通过vc++实现管道通信,解决多进程之间通信的问题。
通过vc++实现管道通信,解决多进程之间通信的问题。 -Through vc++ Realize pipeline communications, multi-process solution to the problem of communication between.
- 2022-12-13 03:20:03下载
- 积分:1
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本例的进程处理器程序实现了进程的列举、进程的切换、启动新的进程、杀死进程、命令行处理等功能。...
本例的进程处理器程序实现了进程的列举、进程的切换、启动新的进程、杀死进程、命令行处理等功能。-cases the processors in the process realized by the enumeration process, the process of switching and started a new process, killing process, the command line processing capabilities.
- 2023-03-27 00:55:03下载
- 积分:1
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For multi
进行多线程编程的好例子,这是多线程的简单例子。-For multi-threaded programming a good example of this is a simple example of multi-threading.
- 2022-03-19 09:39:42下载
- 积分:1
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操作系统实验课程中模拟虚拟存储器的算法
使用先进先出调度算法实现...
操作系统实验课程中模拟虚拟存储器的算法
使用先进先出调度算法实现-experimental courses operating system virtual memory simulation algorithm using FIFO scheduling algorithm
- 2022-01-25 15:37:34下载
- 积分:1
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windows nt serivce code
windows nt serivce code
- 2023-01-08 01:40:04下载
- 积分:1
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How to enumerate all processes of windows os.
How to enumerate all processes of windows os.-How to enumerate all processes of windows o s.
- 2023-07-03 23:50:02下载
- 积分:1
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本程序是在Visua C++6.0继承开发环境下对Windows系统的当前进程进行管理的源代码,类似于系统的任务管理器。能够结束当前任务。...
本程序是在Visua C++6.0继承开发环境下对Windows系统的当前进程进行管理的源代码,类似于系统的任务管理器。能够结束当前任务。-This procedure is in Visua C++ 6.0 development environment to inherit under the current Windows system process to manage the source code, similar to the system Task Manager. To the end of the current task.
- 2022-03-09 18:18:57下载
- 积分:1