发现部分的总和

Goldbach s conjecture： Goldbach(哥德巴赫)曾经提出了一个这样的猜想： 对于2000 以内的正偶数都能够分解为两个素数之和。 要求： 该题是一个猜想，我们不去证明它，而是通过编程序来验证 该猜想是否正确。 输入： 用户从键盘任意输入一个自然数。 输出： 给出满足猜想的两个自然数。-Goldbach conjecture : Goldbach (Goldbach) had raised such a guess : 2000 within the can is even divided into two prime numbers and. Requirements : The title is a guess, we do not prove it, but through programmed to verify the guess is correct. Input : arbitrary user input from the keyboard to a natural number. Output : meet guess is the natural number two.

辛普森复合算法 典型-Simpson typical composite algorithm

棋盘覆盖 applet小程序-chessboard coverage applet small program

一个可以存放任何数据类型的链表类-a store any data type objectlist

Heritrix是一个开源,可扩展的web爬虫项目。Heritrix设计成严格按照robots.txt文件的排除指示和META robots标签。-Heritrix is an open source, scalable web reptiles project. Heritrix is designed in strict accordance with the robots.txt file to exclude directives and META robots tags.

Gauss column principle eliminate for bankdialog systems

多元散射校正算法，用于近红外散射数据处理，增强信噪比-function [Xcorrect]=msc(X,Xref) msc pretreate the samples X with the Multiplicative Scatter Correct Input X:the matrix of the sample spectra to be Correct Xref:the matrix of the sample spectra to be ref Output Xcorrect:the sample spectras was Corrected from the X Programmer: zhimin zhang @ central south university on dec 13 ,2007 Reference: Chemometrics and Intelligent Laboratory Systems 29 (1995) 233-241

0 / 1背包问题是一个N P-复杂问题，为了解决该问题，，将用回溯算法解决该问题。既然想选择一个对象的子集，将它们装入背包，以便获得的收益最大，则解空间应组织成子集树的形状（如图1 6 - 2所示）。该回溯算法与4 . 2节的装载问题很类似。首先形成一个递归算法，去找到可获得的最大收益。然后，对该算法加以改进，形成代码。改进后的代码可找到获得最大收益时包含在背包中的对象的集合。-0/1 knapsack problem is a P-complex issues, in order to solve the problem, and will be used backtracking algorithm to solve the problem. As to the choice of a subset of object, they will load a backpack, in order to obtain the greatest profits, the solution should be organized into space subset of the shape of the tree (Figure 1 6-2 below). The backtracking algorithms and 4. Two loading problem is very similar. Forming a recursive algorithm to get the maximum benefit available. Then, this algorithm is modified to form code. Improved code can be found at the maximum benefits included in the backpack of a collection of objects.

求非终端结点的算法-for non-terminal nodes algorithm