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万年历c实现,简单使用
万年历c实现,简单使用-hefty almanac c realized, simple to use
- 2023-02-01 14:50:03下载
- 积分:1
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mmnbvtrhgfhfgh
mmnbvtrhgfhfgh
- 2022-02-03 20:58:07下载
- 积分:1
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第六章实验二(1)本程序为魔方阵.C
可用来求出所指定大小的魔方...
第六章实验二(1)本程序为魔方阵.C
可用来求出所指定大小的魔方-sixth chapter two experiments (1) the procedure for the Demon phalanx. C can be used to specified sizes calculated by the Cube
- 2023-02-18 06:05:04下载
- 积分:1
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这个是用asp来实现个人注册表单,如果 有什么不对的地方还请各位专家指点!谢谢!...
这个是用asp来实现个人注册表单,如果 有什么不对的地方还请各位专家指点!谢谢!-this is asp to achieve personal registration form, if what is wrong places also asked the experts to guide! Thank you!
- 2023-07-03 20:30:02下载
- 积分:1
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这个开源的H323。
This the H323 open source.
- 2022-02-11 14:26:19下载
- 积分:1
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改文档为PHP文档,可供大家参考使用
改文档为PHP文档,可供大家参考使用 -reform document for PHP files, which can be used as reference documents for the reform PHP documentation for reference use
- 2022-05-14 10:20:08下载
- 积分:1
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DOS下的dma读写驱动,加速硬盘的读写操作。
DOS下的dma读写驱动,加速硬盘的读写操作。-Dma under DOS to read and write drive, hard disk read and write speed up the operation.
- 2022-04-22 19:26:14下载
- 积分:1
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UNIX平台下使用C语言实现的检查主机hostID的函数,可用于程序的加密。...
UNIX平台下使用C语言实现的检查主机hostID的函数,可用于程序的加密。-UNIX platform using C language mainframe hostID inspection functions can be used to process the encryption.
- 2022-04-28 14:58:49下载
- 积分:1
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C语言课程设计
C语言课程设计--泊车管理
这是我们C语言课程设计的一个作业。-C language curriculum design parking management This is our C language curriculum design an operation.
- 2022-02-26 10:10:54下载
- 积分:1
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Find prime numbers prepared by screening the function: void sieve (bool isPrime...
编写筛选查找素数函数:
void sieve(bool isPrime[], int n)
其中isPrime[ ]为一个布尔型数组,n为数组大小。由于2是第一个素数,
所以设置isPrime[0]和isPrime[1]的值为false,并设置其余的元素初值为true。
然后对从4到n-1的每一个i,判断i是否能够被2整除,如果i能够被2整除,则设置isPrime[i]为false。
对从2到n/2的每一个可能的数值重复以上处理,当操作结束时,所有值为true的isPrime[i]所对应的i就是素数,它们将是从筛子中掉下来的。-Find prime numbers prepared by screening the function: void sieve (bool isPrime [], int n) which isPrime [] as a Boolean array, n is the size of the array. Because 2 is the first prime number, so set the isPrime [0], and isPrime [1] a value of false, and set the initial value of the remaining elements of true. And then from 4 to n-1 for each i, to determine whether i can be divisible by 2, if i can be divisible by 2, then set the isPrime [i] is false. From 2 to n/2 possible values for each one to repeat the above processing, when the operation ended, all the true value of the isPrime [i] corresponding to i is a prime number, they will be falling from the sieve in the past.
- 2023-03-02 04:45:03下载
- 积分:1