自己遍的牛顿迭代法求解二元二次方程的程序 迭代步数可以自己设定...

基本的猜数字游戏，有游戏，说明，排行等功能，运行环境DOS-Basic猜数字games, game, description, ranking and other functions, operating environment for DOS

复件 Photoshop CS2图形图像处理教程.rar-Copies Photoshop CS2 image-processing graphics tutorials. Rar

字符集编码的存储结构及其算法描述-storage structure and algorithm description

用来验证轴瓦对中的时候数据的准确性，这是目前国内很少研究的课题，暂时保密的。-Bearing right to verify the accuracy of the data when it is currently very little research. temporarily confidential.

本程序为检测16路输入45~65HZ的信号，并按每路状态输出各自想应路信号-This procedure for the detection of 16 of 45 ~ 65HZ input signal, and the way each state would like to output their signals should be

游戏里面详细描述了九个字，令人发指的数字，几个数字

双进程实现，启动 互相探视，互相启动 如果其中一个被关闭 那么另一个 又开启-Realize dual-process, start to visit each other, each other to start if one was shut down then opened another

经典LabWindows CVI方面的教材《LabWindows CVI开发入门和进阶》一书第7章中的例题源码，使用LabWindows CVI的人用得着。麻烦管理员帮我开通下载功能，我急需要本网站上的labwindows/CVI方面的数据库教程，谢谢！-LabWindows CVI aspects of the classic textbook

关于高斯白噪声下信源数目的估计程序-On the Gaussian white noise source under the estimate of the number of procedures

问题描述: 一杯沸水冷却，圆柱体模型，底面半径0.05m，高0.1m，周围温度20度，初始水温100度 方程是四维输运方程（常数a^2=k/(c*p)，k是热传导系数0.6006焦/（米*秒*度）） 初始条件：t=0时水等于100度 边界条件：1.上下壁都是自由冷却，第三类边界条件，周围温度保持在20度（H=k/h,h取1） 2.杯壁绝热，第二类边界条件 图形显示格式,取过圆柱轴的截面温度变化将其做成动画. -Problem description : a cup of boiling water cooling cylinder model, the bottom radius of 0.05m, 0.1m high. temperature around 20 degrees, initial temperature of 100 degrees equation is four-dimensional equations (a constant ^ 2 = k/(c* p), k is the thermal conductivity coefficient of 0.6006 Coke/(m** seconds degrees)) initial conditions : t = 0 to 100 degree water boundary conditions : 1. upper and lower walls are free cooling, the third boundary conditions, maintain the temperature around 20 degrees (H = k/h, h for 1) 2. Beibi insulation, The second category boundary conditions graphics format, cylindrical shaft for the cross section of its temperature changes caused animation.