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一个用于单片机仿真的源程序代码,主要是用protues进行单片机仿真,对于单片机学习有很大帮助...
一个用于单片机仿真的源程序代码,主要是用protues进行单片机仿真,对于单片机学习有很大帮助-A simulation of the source code for the MCU is mainly carried out with protues MCU simulation study of great help for microcontroller
- 2023-02-27 13:20:03下载
- 积分:1
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VC在线杂志精华12
VC在线杂志精华12-VC-12 best magazines
- 2022-04-12 15:05:46下载
- 积分:1
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C#编程100例源码,有好多例子呀,希望对学习C#的朋友有用,这是第二个包!20个...
C#编程100例源码,有好多例子呀,希望对学习C#的朋友有用,这是第二个包!20个-C# programming source of 100 cases, many examples of it, want to learn C# useful friends, This is the second package! 20
- 2022-03-11 14:58:43下载
- 积分:1
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TMS320C6000 and UART communications, the two solutions.
TMS320C6000与UART的通信,提供了两种解决办法.-TMS320C6000 and UART communications, the two solutions.
- 2022-07-07 17:54:23下载
- 积分:1
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A book called Windows95 communication programming books to learn vc can be helpf...
一本叫Windows95通信编程的书,可以对要学vc的同学有所帮助-A book called Windows95 communication programming books to learn vc can be helpful to students
- 2022-03-18 22:41:50下载
- 积分:1
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学习英语形象记忆法
学习英语形象记忆法-learning English mnemonic image
- 2022-05-24 07:05:10下载
- 积分:1
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《Programming Windows with MFC》附书光盘中的例程。
《Programming Windows with MFC》附书光盘中的例程。-"Programming Windows with MFC" on CD-ROM attached to the routines.
- 2022-03-18 16:53:55下载
- 积分:1
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多的进化算法求解结果
摘
由于演化算法求解多目标优化问题所得结果是一个优化解集―――Pareto最优集,而现有的演化算法收
敛性分析只适合针对单目标优化问题的单个最优解。利用有限马尔科夫链给出了演化算法求解多目标优化问
题的收敛性分析框架,并给出了一个分析实例
-Pick as a result of evolutionary algorithm for solving multi-objective optimization problem the result is an optimized solution set--- Pareto optimal set, and the existing evolutionary algorithm convergence analysis is only suitable for single-objective optimization problem of a single optimal solution. Use of limited Markov chain are given multi-objective evolutionary algorithm for solving optimization problems Convergence analysis framework, and gives an analysis of examples
- 2022-02-22 04:24:58下载
- 积分:1
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Delphi经典编程入门
Delphi经典编程入门-classic entry
- 2022-02-21 23:29:53下载
- 积分:1
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advanced java networking
advanced java networking
- 2023-05-21 02:25:03下载
- 积分:1