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编程精粹
─── Microsoft 编写优质无错C 程序秘诀
Writing Clean Code
─── Microsoft Technique...
编程精粹
─── Microsoft 编写优质无错C 程序秘诀
Writing Clean Code
─── Microsoft Techniques for Developing Bug-free C
Programs
Steve Maguire 著
姜静波 佟金荣 译
麦中凡 校
电子工业出版社
编写优化、高效、无错地代码 2
这份电子书籍由PC Home 俱乐部、C++ Bulider 讨论区数位网友分别整理完成,基本
上完全按照所据译本原貌,极少数文字为通顺起见稍作修改。由于并非一人整理完成,书
中例程各章节代码书写风格可能稍有不同,如指针声明,以下两种写法都存在:
void* pv // ‘*’号与类型说明符相连
void *pv // ‘*’号与变量名相连-programming essence Building Building Quality Microsoft prepared no wrong C program secret Writing Cl ean Building Code Building Techniques for Building Microsoft Developi Vi Bug-free C Programs with Steve Maguire Jiangjingbei Tong Mai Jinrong translation Where were the school electronics industry publishing company optimization, efficient, no wrong code to the two e-books by PC Home Club, C Bulider discussing several netizens were sorted out, basically According to the translation in accordance with the original landscape. very few words for the sake of coherence with some slight modifications. Because a person is not sorted
- 2022-12-26 09:00:03下载
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Pragmatic Version Control use git 的英文原版。Git是今年兴起的分布式版本控制工具,跨平台轻量级但是功能毫不逊色于clearc...
Pragmatic Version Control use git 的英文原版。Git是今年兴起的分布式版本控制工具,跨平台轻量级但是功能毫不逊色于clearcase, SVN这样传统版本控制系统,许多linux操作系统和android的开发小组都在使用git。本书是目前我能找到的最好的入门教材,适合于开发人员和项目管理人员。-"Pragmatic Version Control use git" the English original. those years, git becames a new star of distributed version control tool, cross-platform features lightweight, but no less in the clearcase, SVN version control system so traditional, and many linux operating systems and android development team are using git. This book is the best I can find for new comers, suitable for developers and project managers.
- 2022-11-11 11:15:08下载
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在图书馆管理系统中,要为每个借阅者建立一个账户,并给借阅者发放借阅卡(借阅卡可以提供借阅卡号、借阅者姓名),账户中存储借阅的个人信息、借阅信息以及预定信息。持有...
在图书馆管理系统中,要为每个借阅者建立一个账户,并给借阅者发放借阅卡(借阅卡可以提供借阅卡号、借阅者姓名),账户中存储借阅的个人信息、借阅信息以及预定信息。持有借阅卡的借阅者可以借阅书刊、返还书刊、查阅书刊信息、预定书刊并取消预定,但这些操作都是通过图书馆管理员进行的,也及借阅者不直接与系统交互,而是图书馆管理员充当借阅者的代理与系统交互。在借阅书刊时,需要输入所借阅的书刊名,书刊的ISBN/ISSN号,然后输入借阅者的图书卡号和借阅者名,完成后提交表格,系统验证借阅者是否有效(在系统中存在账户),若有效,借阅请求被接受,然后查询数据库系统,看借阅者所借阅的书刊是否存在,若存在,则借阅者可以借出书刊,建立并在系统中存储借阅纪录。借阅者还书后,删除关于所还书刊的借阅纪录。如果借阅者所借出的书刊已经被借出,借阅者还可预订该书刊,一旦借阅者预订的书刊可以获得,就将书刊直接寄给预订人(为了简化系统,预订书刊可获得就不通知借阅者了)。另外,系统设置了书刊的最长借阅期,如果借阅者归还的时间超过了最长借阅期,要缴纳一定的滞纳金。- Readers card holders can borrow books, return books, check books information, books and planned to cancel, but these operations are carried out by the librarians, and do not borrow directly with the interactive system, but librarians who act as agents to borrow and system interaction. The books, by the need to import borrow books, and books by ISBN/ISSN, and then borrow the book numbers and those who borrow, forms submitted after completion, the system certification Readers whether effective (in the system exist account), if eff
- 2022-03-26 14:50:03下载
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shadow detection paper from net,it is value
shadow detection paper from net,it is value
- 2022-09-22 17:15:02下载
- 积分:1
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一种新的空间离散点集的直接三角剖分方法,不错的论文
一种新的空间离散点集的直接三角剖分方法,不错的论文-a new space of discrete points directly triangulation method, a good paper.
- 2022-09-21 17:15:03下载
- 积分:1
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网上商城系统
网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统网上商城系统
- 2022-03-21 20:19:57下载
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恒润科技公司的基于模型的系统工程与软件工程PPT
恒润科技公司的基于模型的系统工程与软件工程PPT-Hengrun Technology, Inc. Model-based systems engineering and software engineering PPT
- 2022-06-28 02:21:43下载
- 积分:1
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同compress1,针对图像压缩里面中的无损和有损收集到的PDF格式的论文...
同compress1,针对图像压缩里面中的无损和有损收集到的PDF格式的论文-With compress1, for image compression inside the non-destructive and detrimental to the collected papers PDF format
- 2022-03-07 16:49:24下载
- 积分:1
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40个网页设计小技巧,很实用的技巧,适合初学者,
40个网页设计小技巧,很实用的技巧,适合初学者,-40exsample
- 2022-05-28 11:19:38下载
- 积分:1
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还有一个缺陷就是在只知道密文 x 及公钥(n,e)的情况下,只要将 (x^e) mod n 所得余数 s 再不断地循环操作 s = s^e mod n,此运算不...
还有一个缺陷就是在只知道密文 x 及公钥(n,e)的情况下,只要将 (x^e) mod n 所得余数 s 再不断地循环操作 s = s^e mod n,此运算不断地循环 e 次之后,很多情况下都可以循环出原文,只是计算量过余多一些罢了。不过有不少情况下,根本都无须循环 e 次,不过对于1024位的 n 级别来说,e 也是一个相当大的数值,所以循环密文的余数以解得原文是有些不现实。 以上内容仅供参考,如有不实,请予更正-there is a defect in only know that the secret and public key-x (n, e) the circumstances, as long as (x ^ e) mod n from the remaining s to continuously cycle operation s = s ^ e mod n, this constant cycle of Operational e occasion, the very many circumstances can be recycled from the original, but I calculated the volume more than just. There are, however, many instances, simply do not need e cycle times, but for 1024 the level n, e is a very large figure, so secret circle the remainder of the text was obtained in the original is a bit unrealistic. The above is for reference only, if not true, I corrected
- 2022-08-03 02:51:21下载
- 积分:1