获取远程机器名与Mac地址

winsock编程，聊天c/s聊天程序，适合出血者学习winsock-winsock example

基于udp通信的客户端源代码，可以与基于udp通信的服务器端实现通话-server for udp communication

VC++6中用DOM遍历网页中的元素源代码，可以枚举出当前浏览的网页的所有元素。 -VC 6 DOM traversal using the website source code elements, Enumerating up with the current can browse the website of all the elements.

TCP的客户服务器通信程序 一：程序运行过程 1、运行服务器程序，等待客户端发出请求 2、运行客户端程序，输入客户的IP地址，请求连接 3、若连接成功，服务器端显示客户的IP地址及端口号；客户端接收文件并保存在d:clientls.txt下，否则，显示错误信息。 二：程序实现原理 发送端：打开文件，逐一读取字符到缓冲区（缓冲区大小为1024），若文件大于1024，则成块发送；若小于，则直接发送。 接受端：与发送端同理。-TCP client-server communication program one : running a process, running the server and wait for the client to issue two requests, the client operating procedures, the importation of customer IP address, link request, if successful connection, the server-client shows the IP address and port number ; the client receives the document and preserve d : client ls.txt, otherwise an error message. 2 : Principle procedures transmitter : open the file, read each character to the buffer (buffer size for 1024), and if the document is greater than 1,024, then sent into pieces; If less, then sent directly. Receivers : Send-the same reason.

保持党员先进性的网站源码，管理admin/index.asp用户名admin密码admin-advanced nature of Party members to maintain the website source, management admin/index.asp username admin password admin

TCP.IP终端程序源代码-TCP.IP terminal program source code

NioSocket及其开源框架MINA学习总结-MINA open source framework and its NioSocket learning summary

一个Udp广播示例-an example Udp Broadcasting

聊天服务器端程序 与客户端的对应才可以呀-Chat server and client procedures counterparts can ah

非持续CSMA 该协议下，用户在发送帧之前，会先侦听信道的状况，如果没有其他站点发送，它就发送。若信道忙，它就等待一个随机的时间后重复以上动作。 对于某一帧而言，信道是否忙，即是看其绝对时间（FRAMETIME*i+dt）的前一帧时内（FRAMETIME*(i-1)+dt ~ FRAMETIME*i+dt）是否存在发送帧。若无则发送，有则等待一随机时间。 -unsustainable under the agreement, users send frames, will first interception Channel situation, if no other site sent, it sent. If Channel busy, it would wait for a random time to repeat the action. For a frame, whether the busy channel, that is, look at his absolute time (FRAMETIME* i dt) of a time (FRAMETIME* (i-1) dt ~ FRAMETIME dt* i) the existence of this frame. If not then this, then wait for a random time.