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可选自能抢答器,用来对一些节目抢答很有必要,,采用8255编程-optional self Responder, used to some programs Responder is necessary, using 8255 programming, and,

利用PC机的硬件定时8253, 编制秒表延时(0~9秒)程序.要求: 按任意键,开始计时, 在屏幕上以1秒间隔从0到9显示 按ESC键,计时停止.-use of PC hardware-timed 8253, the establishment of a stopwatch Delay (0 ~ 9 seconds) program. Requirements : by the arbitrary button, the timer on screen to a second interval from 0 to 9 shows by the ESC key, a time to stop.

编写一个函数，输入为偶数时，调用函数求,当输入为奇数时，调用函数1(利用指针函数)-The preparation of a function, even when the input, call function for, when the input is odd, one function call (using indicator functions)

本源码是实现的功能的LED的流水，渐变，跑马灯花样-The source is the function of the LED to achieve the water, gradient, pattern Marquee

单片机外部中断的典型应用，proteus仿真，程序，原理图全套。-External interrupt a typical single-chip applications, proteus simulation, procedures, a full set of schematics.

乒乓结构的verilog程序，风格相当好。大家赶紧 下了啊。-Verilog procedural ping-pong structure, style pretty good. Under the U.S. quickly, ah.

一些关于FPGA的重要的PING语句，相当好的东西-Number of FPGA

哲学家就餐问题是由Dijkatra提出并解决的典型同步问题。该问题描述的是有五个哲学家共用一张圆桌，分别坐在周围的五张椅子上，圆桌上有五个碗和五只筷子，他们的生活方式是交替的进行思考和就餐。平时，一个哲学家进行思考，饥饿时便试图取用其左右最靠近他的筷子，只有在他拿到两只筷子时才能进餐。进餐完，放下筷子继续思考。-Dining philosophers problem is presented and solved Dijkatra typical synchronization problems. Description of the problem is that there are five philosophers share a round-table were sitting around the five chair, round table has five bowl and five chopsticks, their way of life is the turn of thinking and eating. Normally, a philosopher to think, hunger when trying to access their nearest him about the chopsticks, only if he can get two chopsticks when eating. End meals, to lay down their chopsticks to continue thinking.

选了一部分比较有代表性的汇编实验题目，都是自己亲手调过的，很有参考价值-More representative selection a part of a compilation of experimental subjects, are transferred off his hand, of great reference value to

Dll木码激发及监视（结束...Dll木码激发及监视（结束-Dll code inspired wood and surveillance (the end of wood ... Dll code to stimulate and monitor (the end of