an increase in C# ASP.NET done a very good procedures

高次方程求解的c代码实现，用于数值分析课，简单实用，可作为参考(Lagrange interpolating polynomial,Bisection algorithm,Newton’s method and Secant method)

某市有一码头，每次仅容一辆船停泊装卸货，由于经常有船等候进港，部分人提出要扩建码头。经过调查历史资料发现，码头平均每月停船24艘，每艘船的停泊时间为24±20小时，相邻两艘船的到达时间间隔为30±15小时，如果一艘船因有船在港而等候1小时，其消耗成本为1000元。经预算，扩建码头大约需要1350万元，故市长决策如下：如果未来五年内停泊船只因等候的成本消耗总和超过扩建码头花费则扩建码头，否则，不予扩建。因此，希望你能够帮助市长做出决策。此问题已知到达的大概时间和大概停泊时间，对于此问题用概率统计的方法来做比较复杂，可用程序随机产生到达时间和停泊时间来模拟未来五年内船的停泊，多次模拟预测停泊情况，以做出决策(。-Problem in a city with a terminal expansion dock, each only allow a boat moored loading and unloading, as often there are waiting boat into port, some people proposed to expand pier. Terminal stopping 24 per month, per vessel berthing time of 24 ± 20 hours, the arrival of two adjacent vessels interval 30 ± 15 hours, if a ship due to boat in the harbor while waiting for one hour, and its consumption cost of 1,000 yuan. The budget of about 13.5 million yuan expansion dock, so the mayor decision as follows: If a ship is moored next five years, the cost of waiting more than the sum of consumption spending is expanding marina pier extension, otherwise, not expanded.)

基于ATMEGA64单片机驱动MCP6S21可编程程控放大器的仿真加ICC源码。(ATMEGA64 microcontroller based programmable programmable amplifier driving MCP6S21 simulation plus ICC source.)

文学研究助手，主要是为文学工作者提供写作上的方便。-literature study

基于modbus通信协议的代码，详细注释，已经与上位机调试通过。

随机生成5000乘客与50000出租车的距离，计算最短距离，并用gpu加速

stm32手动控制机械臂

面这段代码模拟了龟兔赛跑爬山的情况,其中有个时钟触发设置每秒执行一次循环,乌龟的规则是:50% 的机会快走(右移三格) 20% 的机会下滑(左移六格) 30% 的机会慢走(右移一格). 兔子的规则是:20% 的机会睡觉(不移动) 20% 的机会大跳(右移九格) 10% 的机会大滑(左移十二格) 30% 的机会小跳(右移一格) 20% 的机会小滑(左移两格). 其中最先走到整 70 格的胜利,超过 70 格的从头开始 程序在一条线上打印了龟兔移动的轨迹,当两者重合时打印 P 乌龟用 G 表示,兔子用 T 表示. -face this code to simulate the hand of the mountain, which has a clock installed trigger the implementation of a second cycle of the turtle is a rule : 50% chance of brisk walking (3 Georgia shift to right) 20% chance of decline (6 bits grid) 30% chance of walking (a shift to right field) . rabbit is a rule : 20% of the opportunity to sleep (mobile) 20% chance of play (9 Georgia shift to right) 10% of the opportunities in Waterloo (12 bits grid) 30% chance of a small jump (shift to right a grid) 20% chance of a small slip (2 bits grid). One of the most first come the whole grid of 70 victories, more than 70 grid start again from scratch in a process of the turtles online print rabbit mobile track, when the two P Print coincides wit

LCD液晶显示程序，在AT89S52上运行成功，其也可以用于其 他的处理器(LCD liquid crystal display program, run on AT89S52 is successful, it can also be used for the processor)

AIS定位、速度、航向数据解析。可以批量解析并保存。(AIS data decoder。)