包含两个程序，一个用于读管道，一个用于写管道．主要是练习有名管道的使用方法．...

linux下的蓝牙

Linux是一类Unix计算机操作系统的统称。Linux操作系统的内核的名字也是“Linux”。Linux操作系统也是自由软件和开放源代码发展中最著名的例子。严格来讲，Linux这个词本身只表示Linux内核，但在实际上人们已经习惯了用Linux来形容整个基于Linux内核，并且使用GNU 工程各种工具和数据库的操作系统。Linux得名于计算机业余爱好者Linus Torvalds。 -Linux is a Unix-computer" s operating system collectively. Linux operating system kernel is also the name of " Linux" . Linux operating system is also free software and open source development, the most famous example. Strictly speaking, Linux is only the word itself, said Linux kernel, but in reality people have been accustomed to using Linux to describe the whole based on the Linux kernel and the GNU project to use a variety of tools and databases operating system. Linux is named in a computer amateur Linus Torvalds.

典型嵌入式总体框架、嵌入式系统基础、嵌入式ARM体系构架。-Overall framework of a typical embedded, embedded systems based on embedded ARM system architecture.

一个编译器的例子,基于c语言,在linux下开发 现在了简单的c语言例子-a compiler of examples based on c language, the Linux development now under a simple example language c

LINUX下读写NTFS分区的工具。 已经集成了通过LIBCONV库支持中文的代码。-LINUX under the read and write NTFS partition tool. Has been integrated through the support of Chinese LIBCONV library code.

Linux 下编程的三个重要工具（ZT）.rar-Linux Programming three important tools (ZT). Rar

一个tcp通讯公用程序-a common communications procedures.

linux下的声音播放编程应用程序-the voice broadcast programming applications

g.729的编解码c源码（使用intel的ipp包）堪称效率最高。-g.729 arranges decodes the c source code (to use intel the ipp package) to may be called the efficiency to be highest.

PID控制仿真程序 假设一个控制系统：10kg的水，使用最大1kW的电阻丝加热，简化计算，假设焦耳和卡的转化单位为1，而不是4.2加热效率为 Watt [瓦],散热效率为5*T [瓦]设定目标温度为60度， 则100000秒内的温度变化曲线是如何的？-PID control simulation program assumes that a control system: 10kg of water, using hot-filament maximum 1kW resistor to simplify the calculation, assuming the conversion of Joule and card unit of one, instead of 4.2 for heating efficiency Watt [W], thermal efficiency of 5* T [W] set a target temperature of 60 degrees, then the 100000 sec the temperature curve is how?