计算机接口硬件手册

介绍Arcengine二次开发的宝典级电子书-Introduction Arcengine secondary development of the book-class e-book

linux设备驱动程序第二版 希望能帮助大家-linux device driver the second edition to help U.S.

30个有意思的c#小程序-30 Interestingly, a small c# program

C++ 基础教学 希望大家能及时学会 如果需要可以联系我-C++ Basic teaching hope that we can promptly Society can contact me if you need

用JAVA开发WebGIS小应用程序，PDF格式的电子书籍，详细介绍开发过程包括相关代码-WebGIS development using JAVA applets, PDF format e-books, detailing the development process including the relevant code

视频帧内预测的算法公式，详细介绍了帧内编码公式的参数含义及用法-Video intra prediction algorithm formula, the formula described in detail the parameters of intra-coded meaning and usage

firwwork很好的教程-firwwork good Guide

高质量C、C++编程指南-quality C, C Programming Guide

Tug of War(A tug of war is to be arranged at the local office picnic. For the tug of war, the picnickers must be divided into two teams. Each person must be on one team or the other the number of people on the two teams must not differ by more than 1 the total weight of the people on each team should be as nearly equal as possible. The first line of input contains n the number of people at the picnic. n lines follow. The first line gives the weight of person 1 the second the weight of person 2 and so on. Each weight is an integer between 1 and 450. There are at most 100 people at the picnic. Your output will be a single line containing 2 numbers: the total weight of the people on one team, and the total weight of the people on the other team. If these numbers differ, give the lesser first. )

Hibernate Tutorial.Tuturial about Hibernate