Virtual reality three

博弈算法全集，包含经典经济模型中的博弈算法，对其进行描述和实现-game theory algorithm，Contains the classical economic models in the game algorithm is described and the achievement of its

GPS卫星定位模块GR-85开发资料，支持多频率！定位速度快，就是停车漂移！-GPS satellite positioning module GR-85 development information, support multi-frequency! Positioning speed is stopping drift!

在一个划分成网格的操场上，n个士兵散乱地站在网格点上。网格点由整数坐标(x,y)表示。士兵们可以沿网格边上、下、左、右移动一步，但在同一时刻任一网格点上只能有一名士兵。按照军官的命令，士兵们要整齐地列成一个水平队列，即排列成(x,y),(x+1,y),…,(x+n-1,y)。如何选择x 和y的值才能使士兵们以最少的总移动步数排成一列。 实验任务：计算使所有士兵排成一行需要的最少移动步数。-In a grid divided into the playground, n soldiers stood scattered on the grid points. Grid point by the integer coordinates (x, y) express. Soldiers along the edge of the grid, down, left and right moving step, but at the same time any one grid point has only one soldier. In accordance with the officer s command, the soldiers should be neatly列成level queue, that is arranged in (x, y), (x+ 1, y), ..., (x+ N-1, y). How to choose x and y values to make the soldiers with the minimum of the total moves one line up. Experimental tasks: the calculation so that all the soldiers lined up his required minimum moves.

介绍高级数据结构和算法的讲义，advanced.zip- Introduces the high-level construction of data and the algorithm printed lecture, advanced.zip

vc++程序-vc++ procedures

一个讲的不错的JBPM视频讲解,自己看吧，我没空写-jbpm

集成运算放大器应用原理，超星阅览器阅览-Integrated Operational Amplifiers principle, viewing reader Superstar

linux内核模块编程指导 英文版建议-linux kernel module programming guide look at the English proposals

窗口处理技巧大全-window handling skills Daquan

最好的Java教材《Thinking in Java》中文版 ，是chm格式的电子书。-Java the best materials