Another C++ learning book.

对于残缺棋盘的图形演示，可以演示出是如何放入棋盘的-Defective chessboard graphics for presentations, can be a demonstration of how the board Add the

操作系统（2）2、模拟生产者和消费者关系-operating system (2) 2, simulation producers and consumers relations

Please read your package and describe it at least 40 bytes in English. System will automatically delete the directory of debug and release, so please do not put files on these two directory. -Please read your package and describe it at least 40 bytes in English. System will automatically delete the directory of debug and release, so please do not put files on these two directory.Please read your package and describe it at least 40 bytes in English. System will automatically delete the directory of debug and release, so please do not put files on these two directory.

Time Menu Maker! 1.0由于其便捷的操作而成为新近开发出来的软件中的佼佼者，它的功能包括让您轻而易举的制作完全由您自己自行定制菜单，并为您的浏览器添加无以伦比的精彩效果。它不仅支持菜单叠放，还支持框架以及mouseover音响特效等功能。除此之外这个软件还为您特别定制了种类非常齐全的功能。（如滚动显示，限幅器及旋转和旋转模糊等特效）, 主页: http://www.wyka-warzecha.com/-Time Menu Maker! 1.0 due to its easy operation and become a newly developed software in 1987, and its functions include lets you easily produced entirely by your own customized menu, and your browser add unmatched in the exciting results. It is not only stacked menu support, the framework also supports audio and MouseOver effects capabilities. In addition to the software is also customized to your particular type of very complete functions. (Such as rolling, and for limiting rotation and rotating vague effects), Home : http://www.wyka-warzecha.com/

Standard Regular Expression Searcher Addin For VS.NET 2003

聚类（clustering）就是将数据对象分组成为多个类或簇（cluster），在同一簇中的对象之间具有较高的 相似度，而不同的簇中对象差别较大。相异度是根据描述对象的属性值来计算的。距离是经常采用的度量 方式。聚类分析源于许多研究领域，包括数据挖掘，统计学，生物学，以及机器学习。  作为统计学的一个 分支，聚类分析已经被广泛的研究了许多年，主要集中在基于距离的聚类分析。基于k-means（k-平均值）， k-medoids（k-中心点）和其他一些方法的聚类分析工具已经被加入到许多统计分析软件包或系统中， 例如S-Plus，SPSS，以及SAS

richedit

清算登记处拒绝来源

自己做的一个图象变换大小程序,看看就懂.-A simple program for changing size of image by myself.

public class gedebahe { public static void main( String [] args) { for ( ) { int a=-1,b,c //b,c是分解出来的两个数 System.out.print("Please input a oushu:") //输入一个偶数 try { BufferedReader in = new BufferedReader(new InputStreamReader(System.in)) String inputLine = in.readLine() a = Integer.valueOf(inputLine).intValue() }catch (Exception exc) { System.out.println("Sorry,please input a number.") return } if (a%2!=0) { System.out.println("Sorry,please input a oushu.") return } for (b=1 b