16F877使用计时秒表功能的实现，用汇编语言

c++高级编程的源代码，供大家学习c++时使用-c++ high-level programming source code for everyone to learn c++ use

基于WinCE6.0 和C# 的聊天室程序，当在host机和Ebox分别运行程序后，可以在它们之间通信了，都是自己实现的，很不错，对于开始学嵌入式的，想搞Ebox的有很大的帮组哈。-WinCE6.0 and based on the C# Chat room procedures, when the host machine and run the program after the Ebox, respectively, can be communication between them, and realize their own, very well, began studying for the embedded and want Ebox The group has a lot of help and Kazakhstan.

计算CRC4和CRC16的VC程序，其中包含了原创的字符串异或函数，希望对大家有用-CRC16 calculation CRC4 and the VC process, which includes the original string XOR function, in the hope that useful to everybody

本程序的主要功能为求最小乘车路径问题-the main functions of the procedures for the sake of the smallest travel routing problem

我自已设计的时钟程序-clock procedures

这是一个动态改变对话框及其控件大小的好例子，非常的好使-This is a dynamic dialog and its controls to change the size of a good example, so that the very

题目：企业发放的奖金根据利润提成。利润(I)低于或等于10万元时，奖金可提10％；利润高于10万元，低于20万元时，低于10万元的部分按10％提成，高于10万元的部分，可可提成7.5％；20万到40万之间时，高于20万元的部分，可提成5％；40万到60万之间时高于40万元的部分，可提成3％；60万到100万之间时，高于60万元的部分，可提成1.5％，高于100万元时，超过100万元的部分按1％提成，从键盘输入当月利润I，求应发放奖金总数？ 1.程序分析：请利用数轴来分界，定位。注意定义时需把奖金定义成长整型。　　　　　　 -Title: Enterprise of the bonus payment of royalty under the profit. Profit (I) less than or equal to 10 million, prize money will be provided as 10 profits exceeding 10 million, less than 20 million, less than 10 million part of royalty by 10, higher than 100,000 yuan part of the cocoa percentage, 7.5 200000-400000 between, more than 20 million parts, may deduct a percentage of 5 400000-600000 between more than 40 million parts, may deduct a percentage of 3 600000-1000000 between, more than 60 million of the royalty to 1.5, above 100 million, over 100 million parts by 1 percent royalty, from the keyboard input month profit I, Qiu-Ying The total number of bonuses? 1. Program analysis: Please use a few axes to boundarie

一本很好的C++书 适合初学者 -A very good C++ Book suitable for beginners

checking and copying one file to another

C++ How To Program Odd Questions Solution