单电梯控制程序，其中考虑了电梯的上下运行和时间问题

uml课程设计的题目。软件学院的。、 内容就是如题目的样子了……、-uml curriculum design topic. Software Institute. , As if the subject is the look of

面向对象简介，介绍面向对象的基本概念和三大核心特色。适合给有一定基础的人讲解用-OPP PPT

10025，一款使用软件-1005

java写的simplepong,能够实现所有基本功能,不妨下下来学习一下!-simplepong wrote to the realization of all the basic functions, it may be down under study how!

Ragnarok Spirte for game programing

优化设计软件 isight -8.0 的license ,很有参考价值,,多平台 -Optimization design software isight-8.0

good wowmpqview and wowmapview

编写筛选查找素数函数： void sieve(bool isPrime[], int n) 其中isPrime[ ]为一个布尔型数组，n为数组大小。由于2是第一个素数， 所以设置isPrime[0]和isPrime[1]的值为false，并设置其余的元素初值为true。 然后对从4到n－1的每一个i，判断i是否能够被2整除，如果i能够被2整除，则设置isPrime[i]为false。 对从2到n/2的每一个可能的数值重复以上处理，当操作结束时，所有值为true的isPrime[i]所对应的i就是素数，它们将是从筛子中掉下来的。-Find prime numbers prepared by screening the function: void sieve (bool isPrime [], int n) which isPrime [] as a Boolean array, n is the size of the array. Because 2 is the first prime number, so set the isPrime [0], and isPrime [1] a value of false, and set the initial value of the remaining elements of true. And then from 4 to n-1 for each i, to determine whether i can be divisible by 2, if i can be divisible by 2, then set the isPrime [i] is false. From 2 to n/2 possible values for each one to repeat the above processing, when the operation ended, all the true value of the isPrime [i] corresponding to i is a prime number, they will be falling from the sieve in the past.

this is a example about matlab and VC

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