登录
首页 » 其他项目 » 为了方便大家学习,上传了一个贪心算法的算法代码

为了方便大家学习,上传了一个贪心算法的算法代码

于 2022-07-03 发布 文件大小:649.00 B
0 204
下载积分: 2 下载次数: 1

代码说明:

为了方便大家学习,上传了一个贪心算法的算法代码-In order to facilitate them to learn, upload a greedy algorithm algorithms code

下载说明:请别用迅雷下载,失败请重下,重下不扣分!

发表评论

0 个回复

  • 算法源代码比较经典
    算法源代码比较经典-algorithm source code comparison classic
    2022-06-18 07:41:20下载
    积分:1
  • 使用一系列动画
    用数组制作动画-Using an array of animation
    2022-08-06 05:54:09下载
    积分:1
  • data base code postal
    数据库代码邮政管理数据库,邮政编码.mbd以及客户.mbd;使用
    2022-01-31 21:21:25下载
    积分:1
  • 约瑟夫环:编号为1,2,3,…,n的n个人按顺时针方向围坐一圈,每人持有一个密码(正整数)。一开始任选一个正整数作为报数的上限值m,从第一个人开始按顺时针方向自...
    约瑟夫环:编号为1,2,3,…,n的n个人按顺时针方向围坐一圈,每人持有一个密码(正整数)。一开始任选一个正整数作为报数的上限值m,从第一个人开始按顺时针方向自1开始顺序报数,报到m时停止。报m的人出列,将他的密码作为新的m值,从他在顺时针方向上的下一人开始重新从1报数,如此下去,直到所有人全部出列为止。编程打印出列顺序。-Josephus : No. 1, 2, 3, ..., n n clockwise direction by individuals sitting around a circle, each holding a password (positive integers). An optional started as a positive integer reported limits on the number of m, from the first individuals to embark on the clockwise direction since the beginning of a sequence number off, the report m stop. M reported out of the list of his password as a new value m, from a clockwise direction in the next one started from a newspaper a few, like that, until the total of all listed so far. Programming print out the order.
    2022-10-30 01:40:03下载
    积分:1
  • Face objects with thought, with c++ implementation are the basic rules of poker
    用面相对象的思想,用c++是实现扑克牌的基本玩法-Face objects with thought, with c++ implementation are the basic rules of poker
    2022-03-18 06:40:22下载
    积分:1
  • .修改kspublib.jar文件中DBConfig.xml,将数据库配置为自己的数据库。 2.将optiontree.jar,kspublib.jar(需要x...
    .修改kspublib.jar文件中DBConfig.xml,将数据库配置为自己的数据库。 2.将optiontree.jar,kspublib.jar(需要xml解析器xerces.jar)拷贝到应用的web-inf/lib目录下-. Kspublib.jar to amend the document DBConfig.xml, the database is configured to its own database. 2. Optiontree.jar, kspublib.jar (need xml parser xerces.jar) copies to the application WEB-INF/lib directory
    2022-06-30 23:09:05下载
    积分:1
  • ti 的单相电机调速程序F24x ACI1_1 Single Phase ACI Motor Control using Constant VHz...
    ti 的单相电机调速程序F24x ACI1_1 Single Phase ACI Motor Control using Constant VHz-ti single-phase motor procedures F24x ACI1_1 Single Phase ACI Motor Control using Constant VHz
    2022-04-15 21:36:37下载
    积分:1
  • 实现游戏中对机器人进行矩形运动的智能控制算法
    实现游戏中对机器人进行矩形运动的智能控制算法-realization of the game for robot movement rectangular intelligent control algorithm
    2023-03-13 19:00:04下载
    积分:1
  • Find prime numbers prepared by screening the function: void sieve (bool isPrime...
    编写筛选查找素数函数: void sieve(bool isPrime[], int n) 其中isPrime[ ]为一个布尔型数组,n为数组大小。由于2是第一个素数, 所以设置isPrime[0]和isPrime[1]的值为false,并设置其余的元素初值为true。 然后对从4到n-1的每一个i,判断i是否能够被2整除,如果i能够被2整除,则设置isPrime[i]为false。 对从2到n/2的每一个可能的数值重复以上处理,当操作结束时,所有值为true的isPrime[i]所对应的i就是素数,它们将是从筛子中掉下来的。-Find prime numbers prepared by screening the function: void sieve (bool isPrime [], int n) which isPrime [] as a Boolean array, n is the size of the array. Because 2 is the first prime number, so set the isPrime [0], and isPrime [1] a value of false, and set the initial value of the remaining elements of true. And then from 4 to n-1 for each i, to determine whether i can be divisible by 2, if i can be divisible by 2, then set the isPrime [i] is false. From 2 to n/2 possible values for each one to repeat the above processing, when the operation ended, all the true value of the isPrime [i] corresponding to i is a prime number, they will be falling from the sieve in the past.
    2023-03-02 04:45:03下载
    积分:1
  • laser_damage_te用fdtd方法研究激光损伤
    laser_damage_te用fdtd方法研究激光损伤-laser_damage_te fdtd method using laser injury
    2022-11-28 09:55:03下载
    积分:1
  • 696516资源总数
  • 106914会员总数
  • 0今日下载