用VS.NET 2003开发的一个伟大的C++软件，帮助很多初学者。快点…

基于OPENCV的简单的动态识别从0到9的手势，识别率高。能够识别剪刀，包布，锤，并与电脑进行互动游戏。适合初学者对手势识别的学习与研究。

这个小程序可以帮你统计你输入的总的字符数和英文（中文）字符数！-This little program can help you statistics you enter the total number of characters and English (Chinese) characters!

使用pci8333数据采集卡的水箱测试程序-The use of data acquisition card pci8333 tank test procedure

最好的地理数据库之一；

里面有数据操作的各个例子-inside data operation of the various examples

给定的字母表A 由26 个小 写英文字母组成A={a,b,…,z}。该字母表产生的升序字符串是指字符串中字母按照从左到 右出现的次序与字母在字母表中出现的次序相同，且每个字符最多出现1 次。例如， a,b,ab,bc,xyz 等字符串都是升序字符串。现在对字母表A 产生的所有长度不超过6 的升序 字符串按照字典序排列并编码如下。 1 2 … 26 27 28 … a b … z ab ac … 对于任意长度不超过6 的升序字符串，迅速计算出它在上述字典中的编码。 -Given the alphabet A by the 26 lowercase letters of the alphabet composed of A = (a, b, ..., z). Generated by the alphabet ascending string refers to the letter string in accordance with the order from left to right appears in the alphabet and letters appearing in the same order, and each character appears a maximum of 1 times. For example, a, b, ab, bc, xyz, etc. are ascending string string. Alphabet A have now all the length of not more than 6 strings of ascending order in accordance with the dictionary and coding sequence is as follows. 1 2 ... 26 27 28 ... ab ... z ab ac ... for any length of not more than 6 strings of ascending quickly calculate it in the dictionary encoding.

一个很简单的windows程序 看了 是一种幸福-a very simple procedure windows to be read a blessing

巧妙实现windows程序的重复允许限制，使每个实例只能允许一次。-cleverly achieved windows of repeat procedures allow restrictions, each allowing only one example.

根据特定的波形类似正弦/三角波的这项计划将不断消耗的CPU资源。

使用JAVA语言实现下列功能的系统 a) 系统能接受用户输入一个文件名，该文件名对应的文件A可能包含中文，英文字符，换行回车等字符。 b) 系统在确认用户输入的文件A存在后对文件A进行处理，生成另外一个文件B,要求文件B显式包含文件A的所有内容，并且不改变文件A中的已经有的内容。 c) 系统在文件A不存在的情况下，可以发现B中保留的A的内容被修改过。这种修改包括删除/增加A的某行信息，在A的内容中增加/删除/修改某个字符。-use JAVA following a function of the system) system will accept user input a name, the name of the paper document may contain A Chinese and English characters such as newline characters enter. B) System user input in identifying the existence of a document after document A pair of processed produce another document B, B requested documents Explicit document contains all the elements of A and A does not change the document has some content. C) A system in the document did not exist circumstances, it can be found B of A to retain the content has been modified. Such changes include the deletion/A increased to a certain line of information in the contents of A Increase/delete/change certain characters.