api function Xiang Jie, including the use of api functions, a simple api functio...

在工业生产控制系统中，有许多需要定时完成的操作，如定时显示当前时间，定时刷新屏幕上的进度条，上位 机定时向下位机发送命令和传送数据等。特别是在对控制性能要求较高的实时控制系统和数据采集系统中，就更需要精确定时操作。-in industrial production control system, there are many needs time to complete the operation, such as the timing shows the current time, regularly updated progress on the screen of the PC regular crew sent down orders and transmit data. Especially in the control of the high performance requirements of real-time control system and data acquisition system, the need for more precision timing operation.

JBuilder 9.0程序设计源代码--许多优秀的java源代码--圆你java程序员梦-JBuilder 9.0 programming source code-- many outstanding java source code-- you java programmer Yuan Meng

主要有学籍管理、成绩录入和统计（按学号、普通总分、标准分进行排序）、毕业生学籍管理和查询、学生德育考核和操行评语、学生奖励处分记录。设置动态查询功能，由用户自行设置三个查询条件进行精确查询和模糊查询。本系统数据文件全部存贮在数据库中，不受服务器读写权限的限制。保护了服务器的安全。本系统现在有四个版本的软件。-There are student status management, entry and statistical results (by Student ID, general total score, the standard sub-sort), graduate student status management, and information, assessment and student moral conduct reviews, student awards punishment record. Set dynamic query functionality, by the user to set their own precise three query query and fuzzy query. The system data files all stored in a database, not the server to read and write access restrictions. To protect the server" s security. The system now has four versions of the software.

插入u盘自动拷贝到指定目录,带有文件过滤功能

快递管理系统，使用VC,MFC,C++技术开发-express management system, using VC, MFC, C technology development

容器类经典实例演示。-container class classic examples demonstrate.

一个用来方便保存文本内容的小程序,包括源代码和程序.-one used to facilitate the preservation of the text of small programs, including source code and procedures.

web download实用工具，非常好用-web download utility, very easy to use

实现物流信息系统的签单回单管理，自动跟踪客户签单跟踪的目的-Implementation of logistics information system signing back to a single management, automatic tracking of the customer to track the purpose of signing

求解迷宫问题，输入一个迷宫矩阵，矩阵只有1和0，1表示通行，0表示不行。是同过递归求解-Maze solving the problem, enter a maze matrix, matrix, said the passage of only one, and 0,1, 0 not do that. Been solved with the recursive