工程名称:search route.spj中的重要程序代码！

这是粒子群算法的一个源程序，程序很简单，已经运行过了，可以用，对初学者是个不错的程序-This is a source particle swarm optimization algorithm, the program is very simple, has been running over us, we can use, for beginners is a good program

数据库模板：关于整体分析，模块设计等。这是设计的第一份-Database Templates: With regard to the overall analysis, module design. This is the design of the first

分形维数的估算软件FD3，C++源代码，具有很好的学习价值，是一切分形科学工作的基础。-fractal dimension estimation software FD3, C source code, with good learning value of all fractal science work.

天文观测软件，可以根据爱好者所在地点随时准确地进行定位并预测未来星空图。-Astronomical Observatory of software, according to the location at any time lovers accurately locate and predict the future Star Chart.

拼图游戏，教材上的，比较经典，希望大家支持一下。-Jigsaw puzzle, teaching materials on comparing the classic I hope you will support you.

一个关于人工智能-神经网络的例子及其算法程序 -on an artificial intelligence-examples of neural network algorithms and procedures

For solving the following problem: "There is No Free Lunch" Time Limit: 1 Second Memory Limit: 32768 KB One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free. However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.

  超市进销存管理系统应该具有以下功能： l          前台销售结帐。 l          基本信息管理。 l          基本信息查询。 l          日结查询。 l          超市小票打印。

用c++做的图书馆管理系统，英文界面 功能包括注册 借书 还书 书本登记等--Librariy Management System

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