Understand the Linux kernel (the third Sa'edi tion)

UML 相关，组件框架-UML related components framework

GNU make的编写详解，对编写makefile很有帮助。-GNU make the preparation of detailed, helpful to the preparation of makefile.

本PDF详细叙述了如何建立高效的存储过程,为高效的web开发打下良好基础-the PDF detailed description of how to establish an efficient storage process for the efficient development of the web has laid a good foundation for

linux核心中文手册，图文并茂，文字精练易懂，很适合初学者．-linux core Chinese manuals, illustrations, text scouring understandable, which is perfect for beginners.

C与C++标准库指南和C函数查询简单 方便-C and C++ standard library guidelines and C function query

简单的讲解语言,非常实用,使你在短期内就能熟练掌握其变成技巧-simple language to explain, very practical, so that you will soon become familiar with and understand their skills

是该书上的例子源码-book is the example source code

舞伴问题假定在一舞会上，男士排成一队，女士排成一队。跳舞开始时，依次从男队和女队的队头各出一人配成舞伴。若两队初始人数不相同，则较长的那一队中未配对者等待下一轮舞曲。设计要求：模拟上述舞伴系统，并能计算对于任何男士A和女士B在哪一轮舞曲中的k次跳舞？ -Question assumes that a dance partner, the men line up a team, ladies and line up a team. Dancing began, followed by men" s and women" s team from the team dubbed the first one from each partner. If the initial number of teams is not the same, then the longer of that team who is not waiting for the next round of the dance pairs. Design requirements: Analog the partner system, and can calculate for any men" s A and women dance in B in which a k-dance?

用vc++编的认证系统，匆忙编的，不好之处，请原谅-with vc series of the certification system, hastily series, it not very good, please forgive

一本介绍java 的好书~~~~~~~~~~~ 喜欢java的同志必看，虽然是英文，但是慢慢看拉-a briefing books java java ~~~~~~~~~~~ like the comrades Watchable, though English, but slowly can pull Albion