仓库管理系统

大学三年级操作系统实验1进程调度，三种方法都有-University of third-year operating system process scheduling experiment 1, three methods have

Library Management System 1

这是一个学生vb考试系统的源代码，功能还不是很完善，如有欠缺请指正。谢谢！-students vb test system source code, function is not perfect, if not please correct. Thank you!

五子棋游戏源代码，可在wince平台上运行，是一款非常好的游戏-Renju game source code can be run on wince platform, is a very good game

一个完全免费的条码打印控件-a free barcode printing controls

未经证实的delphi帮助文档，有一定的利用参考价值，希望对各位的delphi应用有所帮助。-unconfirmed delphi help files, the use of a certain value, and I hope to you delphi application help.

对二维码进行识别，将简单的二维码图像进行剪切，量化，去噪，矫正，最后识别出二维码的信息。

发射部分采用锁相环式频率合成器技术， MC145152和MC12022芯片组成锁相环，将载波频率精确锁定在35MHz，输出载波的稳定度达到4×10-5，准确度达到3×10-5，由变容二极管V149和集成压控振荡器芯片MC1648实现对载波的调频调制；末级功放选用三极管2SC1970，使其工作在丙类放大状态，提高了放大器的效率，输出功率达到设计要求。-Part of the launch phase-locked loop frequency synthesizer using technology, MC145152 and MC12022 PLL chips to lock in the exact carrier frequency 35MHz, the output carrier to achieve the stability of 4 × 10-5, reaching the accuracy of 3 × 10-5 by the varactor diode V149 and integration to achieve MC1648 chip VCO FM modulation on the carrier selection transistor amplifier at the end of class 2SC1970, to work in the C state to enlarge and improve the efficiency of the amplifier output power to meet the design requirements.

KalmanFilter 递归程序，非常经典-KalmanFilter recursive procedures, very classic

学生成绩核算系统的设计与实现（25） 要求：（1）按班级按课程从文件中读入相应的平时成绩、期中考试成绩和期末考试成绩。 （2）三个成绩对总评成绩的百分比被定义为常数，各占总成绩的30 、30 和40 。 （3）计算每位学生的总评成绩。 （4）计算该班级本课程的总平均成绩。 （5）计算处于优、良、中、及格、不及格的学生人数以及占总人数的百分比。其中100-90为优，89-80为良，79-70为中，69-60为及格，60分以下为不及格。 （6）按要求输出成绩在优、良、中、及格、不及格各区间的学生学号、成绩。-The student achievement calculation system s design with realizes (25) Request: (1) reads in the corresponding usual result, the midterm examination result and the terminal examinations result according to the class and grade according to the curriculum from the document. (2) three result are defined to the general appraisal result s percentage as the constant, occupies the overall result respectively 30 , 30 and 40 . (3) calculates each student s general appraisal result. (4) calculates this class and grade this curriculum the population mean result. (5) calculates the student population which is in superiorly, good, passes an examination, does not pass an examination as well as accounts for the total number of peop