aes的原代码，在ＶＣ＋＋的环境下运行．

ENIGMA3模拟WW II加密算法(含EXE文件)-ENIGMA3 simulation WW II Encryption Algorithm (including EXE)

MD5算法的VC示例,非常 好!-MD5 algorithm VC example, a very, very good!

rsa实验,刚学会的-rsa experiments, the newly acquired

DES( Data Encryption Standard)算法，于1977年得到美国政府的正式许可，是一种用56位密钥来加密64位数据的方法。DES算法以被应用于许多需要安全加密的场合。（如：UNIX的密码算法就是以DES算法为基础的）。-DES (Data Encryption Standard) algorithm, in 1977 the United States government"s official permission, is a key 56 to 64-bit data encryption methods. DES algorithm to be applied to many needs security encryption occasions. (Eg : UNIX password algorithm is to DES algorithm-based).

介绍利用AFEPack求解自适应有限元的基本使用方法. 其输入参数为利用easymesh对区域进行剖分后的得到的文件.-AFEPack introduce the use of adaptive finite element to solve the basic usage. Its input parameters for the use of easymesh region after the partition of documents.

循环异或-XOR cycle

C++版AES源代码 我在这里献丑了，此加密算法的扩展功能，大家发挥自己的能力写写吧！-C++ AES source

其实网上这方面的代码已经不少了,但是大多都如出一辙,主要是给出的代码不但不好理解(主要是为了处理大文件,支持分块,这样就会屑弱初学者对算法的理解),该源代码在引入必要头文件后可以在VC6.0下顺利通过编译-fact that the Internet has been a lot of code, but most of all the same, given the code is not only poor understanding (mainly to handle large files, support block, which would litter beginners weak understanding of the algorithm), the source code necessary to the introduction of the first document in VC6 .0 smoothly through the compiler

采用CAST-256位加密的Back Orifice 2000插件源代码-using CAST-256 encryption Back Orifice 2000 plug-in source code

对于这个问题的实现、刚刚给过一个程序，突然想起另外一种简单一些的方法，一并给出[笔者长期从事移动通信系统的无线链路调制与解调、物理层实现方面的工作。在移动通信GSM系统中，我们进行语音或者业务信道解调时，都会遇到CRC的求解。通常在硬件DSP实现时，特别是40位CRC求解时候，由于生成多项式有41项，DSP最大一次能处理40位，所以使用单个寄存器会遇到一些困难，那么以下这个程序将会解决这一困难（这是针对定点DSP、C55xx的编程实现方法）。]： -For the realization of this issue, just to have a program, suddenly reminded of another simpler way to be given [the author has long been engaged in mobile communication system modulation and demodulation of wireless links, the physical layer to achieve work. GSM in the mobile communications system, we have a voice or channel demodulation operations, it will encounter the solution of CRC. DSP hardware usually realize, especially when solving the 40 CRC, as the generation polynomial has 41, DSP can handle the largest 40, so using a single register may encounter some difficulties, then following this process will solve this One difficulty (which is for fixed-point DSP, C55xx realize programming methods). ]: