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Some code on how to write a small summary of the recommendations and hope to be...
是一些关于如何写好代码的小建议和总结,希望能够有用!-Some code on how to write a small summary of the recommendations and hope to be useful!
- 2022-08-22 04:07:18下载
- 积分:1
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linux
linux-c语言开发时用到的函数集合.可以有助快迅速开发程序所要的函数-linux-c
- 2022-09-10 11:30:03下载
- 积分:1
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OFDM ―― OFDM(Orthogonal Frequency Division Multiplexing)即正交频分复用技术仿真。...
OFDM ―― OFDM(Orthogonal Frequency Division Multiplexing)即正交频分复用技术仿真。-OFDM- OFDM (Orthogonal Frequency Division Multiplexing) that is orthogonal frequency division multiplexing simulation.
- 2022-10-28 17:35:04下载
- 积分:1
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DAB Channel Decoder Implementation Using FPGA
and Its Testing Platform Buildup
DAB Channel Decoder Implementation Using FPGA
and Its Testing Platform Buildup
- 2022-02-02 03:02:59下载
- 积分:1
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3COM的使用和帮助文件,是将交换器的说明,图例集全。
3COM的使用和帮助文件,是将交换器的说明,图例集全。-3COM use and help files is to exchange the note Figure throughout.
- 2022-01-24 14:07:13下载
- 积分:1
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literacy ini format configuration file
读写ini格式的配置文件-literacy ini format configuration file
- 2022-04-01 01:14:45下载
- 积分:1
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atm的UML设计~~~可以参考一下写得蛮好的
atm的UML设计~~~可以参考一下写得蛮好的-atm UML design ~ ~ ~ can refer to the written very good
- 2022-12-23 11:00:03下载
- 积分:1
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DICOM3.0标准中文版1
DICOM3.0标准中文版1-DICOM3.0 a Chinese version
- 2023-08-14 10:35:04下载
- 积分:1
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4 reports the experimental data structure, content or subject of the experiment...
数据结构实验4报告,实验内容或题目
l、随机产生n=100,200,300,1000,2000个整数并存于数组r[1..n]中。对主要查找算法(顺序查找、插入排序、冒泡排序、堆排序、快速排序)进行实验比较,计算出平均比较次数、平均移动次数及执行时间。由程序自动计算,由手工计时。
2、对实验结果数据进行对比分析。
主要内容是-4 reports the experimental data structure, content or subject of the experiment l, randomly generated integers n = 100,200,300,1000,2000 co-exist in the array r [1 .. n] in. On the main search algorithm (the order of search, Insertion Sort, Bubble Sort, Heap Sort, Quick Sort) for the comparison, the calculated average number of comparison, the average mobile number and execution time. Automatically calculated by the procedure by manual timing. 2, the experimental results the data were analyzed. Main content
- 2022-02-21 15:58:11下载
- 积分:1
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* Use Lagrange interpolation method based on N
* 用拉格朗日插值法依据N个已知数据点即使函数值
* 输入: n--已知数据点的个数N-1
* x--已知数据点第一坐标的N维列向量
* y--已知数据点第二坐标的N维列向量
* xx-插值点第一坐标
* 输出: 函数返回值所求插值点的第二坐标
-* Use Lagrange interpolation method based on N-known data points even function* Input : n-- known data points the number N-1* x-- known data points of the first N-dimensional coordinates listed Vector* y-- Known number stronghold of the second N-dimensional coordinates listed Vector* xx-point first interpolation* Coordinate output : function return values for the second interpolation point coordinates
- 2022-05-30 22:13:24下载
- 积分:1