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9325 IC 完整初始化 解析度240*320
9325 IC 完整初始化 解析度240*320-9325 IC initialization complete resolution 240* 320
- 2022-03-13 20:20:06下载
- 积分:1
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这是一个来源的。运行后,点击按钮将隐藏…
这是一个Delphi做的源码.程序运行后,单击按钮,将会隐藏"开始"菜单和状态栏中的时钟.很有趣.-This is a source of Delphi done. After running, click the button will hide "start" menu and status bar clock. Very interesting.
- 2022-10-05 00:45:04下载
- 积分:1
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文章介绍了海洋界面参数估计及传播损失的射线声学预报方法...
文章介绍了海洋界面参数估计及传播损失的射线声学预报方法-Article introduced the marine interface parameter estimation and dissemination of the loss of forecasting methods for acoustic ray
- 2022-04-13 09:50:56下载
- 积分:1
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GBA game Tetris FOSS
GBA游戏俄罗斯方块源码-GBA game Tetris FOSS
- 2022-07-19 15:39:50下载
- 积分:1
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uva10324解法(提共題目和解法程式)
題目說明:給你一連串僅包含0和1的字串 (字串長度最大到1000000,字串從第0個字元開始),要請你回答我們在第i個和第j個字元之間(包含第i個和第j個)、 是否所有的字元均相同 (均為1或均為0)。如果均相同請回答Yes、 否則請回答No。输入每筆測試資料的第一列為一個僅包含0和1的字串,下一列有1個整數n 代表對於上一列字串以下有n個問題。皆下來的 n 列每列有2個非負的整數分別代表 i和 j。输出對每一列測試字串,請先輸出第幾個的案例。然後根據 n 個問題回答肯定或否定的。解法:1.用获取讀入整行字串輸入、 並計算長度2.先判斷第 0 個位置,为 0 則把 0 存入另一個整數陣列,为 1 則存 13.用迴圈把字串陣列轉換存到整數陣列、 遇到字元 0 則值不變、 遇到字元 1 則加 14.欲判斷的i、 j位置都為字元 0、 且整數陣列i、 j位置的值相同、 代表有一連串 0、 輸出是5.欲判斷的i j位置都為字元 1,且整數陣列i、 j位置的值相減為i、 j的差、 代表有一連串 1,輸出是6.其他情況輸出号
- 2022-05-06 12:04:30下载
- 积分:1
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动感相册 Flash版 含Fla源文件
网页上的Flash动感相册,基于Flash+XML技术实现,源文件来自国外。附有FALSH源文件,点击相册任意一个小图,会动感切换出大图,用到个人博客或者图片展示挺不错的。源码包中包含了fla源文件、PSD素材文件和FONT字体文件。测试效果请打开_DEPLOY目录。
- 2023-04-07 07:35:04下载
- 积分:1
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ulink2++,是ARM仿真器,很流行最牛的ARM开发者必备的工具,这里是制作它的SCH原理图...
ulink2++,是ARM仿真器,很流行最牛的ARM开发者必备的工具,这里是制作它的SCH原理图-ulink2++, is the ARM emulator, it is the most popular cattle ARM developers the necessary tools, here is the production of its schematic diagram SCH
- 2022-03-17 01:08:57下载
- 积分:1
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一个简单的文本编辑的教学源代码,,希望可以帮组大家学习
一个简单的文本编辑的教学源代码,,希望可以帮组大家学习-a simple text editor to the source code teaching, the hope that we can help groups learn
- 2022-01-31 19:24:00下载
- 积分:1
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VC++将DialogBar添加到对话框中
VC++将DialogBar添加到对话框中,运用最简单的方法来实现,对新手绝对是有用的基础技巧。
- 2023-04-25 14:15:03下载
- 积分:1
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解决以下问题:
For solving the following problem:
"There is No Free Lunch"
Time Limit: 1 Second Memory Limit: 32768 KB
One day, CYJJ found an interesting piece of commercial from newspaper: the Cyber-restaurant was offering a kind of "Lunch Special" which was said that one could "buy one get two for free". That is, if you buy one of the dishes on their menu, denoted by di with price pi , you may get the two neighboring dishes di-1 and di+1 for free! If you pick up d1, then you may get d2 and the last one dn for free, and if you choose the last one dn, you may get dn-1 and d1 for free.
However, after investigation CYJJ realized that there was no free lunch at all. The price pi of the i-th dish was actually calculated by adding up twice the cost ci of the dish and half of the costs of the two "free" dishes. Now given all the prices on the menu, you are asked to help CYJJ find the cost of each of the dishes.
- 2022-12-06 21:00:03下载
- 积分:1