It is a informix esql/c technology development of banking procedures code.

sbc2410 移植u-boot 1.3.4 的修改部分 需要在borad/sbc2410x/Makefile 下添加编译nand.o -sbc2410 transplant u-boot 1.3.4 changes borad/sbc2410x/Makefile part of the need to add compiler nand.o

linux 1.0 源代码-Linux 1.0 source code

linux环境下 多线程的简单使用，可以学习多线程的一般方法-linux environment using a simple multi-threaded, multi-threading can learn the general approach

介绍了嵌入式linux文件系统的知识，谈到了flash文件系统的设计方法-Introduced the embedded knowledge of linux file system, when it comes to a flash file system design methodology

本程序主要可以对一个c语言程序中的括号和注释情况进行检查，可以快速地发现原程序 * 中隐含的语法匹配性错误，可以根据检查结果，对不匹配的括号进行修改，最快速度地将 * 程序修改正确。同时本程序也可以象wc程序一样对一个程序进行计数统计，得到一个文件 * 的行、单词、字节的统计结果。-this procedure can be a major c language program brackets and the inspection of the Notes can be found quickly to the original* implied matching syntax errors, according to test results that do not match the brackets revised to be the fastest speed* revising the procedures correctly. While this procedure may also wc procedure as a process of counting statistics, to be a document* lines, words, byte of the data.

Non-Networked File System在几个非网络的（或慢网络的）Unix 计算机上提供了一个兼容的文件系统。-Non-Networked File System (or slow network) on the Unix computer has provided a compatible filing system in several non- networks.

linux下的聊天程序，server端和client端下载后直接编译就可运行。其他为必需的调运函数，也必须调用并运行。-under linux chat procedures, server and client-side download operation can be directly translated. Other necessary for the transportation function, you must call and run.

LINUX 1.0 内核c源代码.ZIP-LINUX 1.0 kernel c source code. ZIP

优龙Intel Xscale PXA270 开发平台 LINUX源码, 包括 平台用户手册, PDF原理图, kernel, driver代码. 非常有参考价值.-Intel Xscale PXA270 gifted Liuzhou LINUX-source development platform, including the platform, user manual, PDF schematic diagram, kernel, driver code. A very valuable reference.

int show_char(int n, const char *name, chtype code) { const int height = 16 int row = 4 + (n height) int col = (n / height) * COLS / 2 mvprintw(row, col, " *s : ", COLS/4, name) addch(code) return n + 1 }- int show_char(int n, const char*name, chtype code) { const int height = 16 int row = 4+ (n height) int col = (n/height)* COLS/2 mvprintw(row, col, "*s : ", COLS/4, name) addch(code) return n+ 1 }