罗列了模式识别第四章相关公式，方便老师做幻灯

本文详细讲解了学习ARM时遇到的几点问题，挺好的资料。-This article gave a detailed study and ARM encountered a few problems, quite good information.

《C++标准库》的附带光盘，其中基本涵盖了C++中出现的标准库的解释，不管对于C++的初学者还是C++的熟练者都有相当的帮助-"C standard library" of the CD-ROM attached, which basically cover the C standard library"s interpretation, no matter for the beginners C or C Players have considerable help

C++ Primer中文版及题解.part4-C Primer and that the Chinese version of solutions. Part4

java入门必读-java entry reading

将BMP文件转换为JPG文件，可以在程序中调用，不用再打开WINDOWS自动的画图版了。-BMP files will be converted to JPG files, you can call in the procedure, no longer automatically open the WINDOWS version of the drawing.

在一个划分成网格的操场上，n个士兵散乱地站在网格点上。网格点由整数坐标(x,y)表示。士兵们可以沿网格边上、下、左、右移动一步，但在同一时刻任一网格点上只能有一名士兵。按照军官的命令，士兵们要整齐地列成一个水平队列，即排列成(x,y),(x+1,y),…,(x+n-1,y)。如何选择x 和y的值才能使士兵们以最少的总移动步数排成一列。 实验任务：计算使所有士兵排成一行需要的最少移动步数。-In a grid divided into the playground, n soldiers stood scattered on the grid points. Grid point by the integer coordinates (x, y) express. Soldiers along the edge of the grid, down, left and right moving step, but at the same time any one grid point has only one soldier. In accordance with the officer s command, the soldiers should be neatly列成level queue, that is arranged in (x, y), (x+ 1, y), ..., (x+ N-1, y). How to choose x and y values to make the soldiers with the minimum of the total moves one line up. Experimental tasks: the calculation so that all the soldiers lined up his required minimum moves.

FastReport中文开发指南-FastReport Chinese Development Guide

PL/SQL开发和运行环境、跟踪和调试、使用子程序和包、数据库触发器-PL/SQL development and runtime environment, tracking and debugging, and use subroutine packages, database triggers

matlab 图像处理函数,所有相关函数应用示例。可作为工具查阅。-matlab image processing function, the function of all relevant application examples. Can be used as tools for access.

OpenGL和MFC的编程源码的详细过程-OpenGL and MFC programming source of detailed process