游戏 拼图 源代码，wince平台，很好哦

10K到5MHz的频率测量，误差在0.05 之内。用ATmega16实现-10K to 5MHz frequency measurement error of 0.05 . Implementation with ATmega16

哈夫曼数图形输出,建立,查询,删除,课程设计资料-Huffman few graphics output, the establishment of inquiries, delete, curriculum design information

实现实包络对齐。采用插值，拟合处理。更加精确的对齐-To achieve solid envelope alignment. Using interpolation, fitting handle. More accurate alignment

C++开发的。农夫过河。一个农夫带着一只狼，一只羊和一些菜过河。河边只有一条一船，由 于船太小，只能装下农夫和他的一样东西。在无人看管的情况下，狼要吃羊，羊要吃菜，请问农夫如何才能使三样东西平安过河。 -C development. Farmers across the river. A farmer with a wolf, a goat and some vegetables across the river. Only a river boat, the boat is too small to install under the farmer and his thing. Unattended circumstances, the wolf to Qiyang, the sheep to the meal, ask the farmers how to make three things safely across the river.

资源描述调试了，没有错误，解释也很详细，不懂的可以联系我，很简单

命令行下可以解读TCP数据报内容的Sniffer-command line can be interpreted as TCP data reported to the Sniffer

连接发电机组控制台的后台程序，要求控制器支持MODBUS协议-Generating units connected console daemon requires the controller to support the MODBUS protocol

MS12864J的C51显示程序，这两个程序我改了好久，可是总显示不了，那位高手帮帮忙吧，谢谢，谢谢。-Two C programs of MS12864J,not compiled.Anyone help me?

sabpyuanma 资料 资料-sabpyuanma information information information

某个公司采用公用电话传递数据，数据是四位的整数，在传递过程中是加密的，加密规则如下： 　　　每位数字都加上5,然后用和除以10的余数代替该数字，再将第一位和第四位交换，第二位和第三位交换。-A company to transfer data using public telephones, the data is four integers, in the transmission process is encrypted, encryption rules are as follows: Each figures with five, and then divided by 10 instead of the more than a few numbers, and then The first and fourth exchange, the second and third exchange.