一个WEB在线文件管理系统.内里主要用到的ASP.NET的一些技术.

一种类似pad2的的字处理程序，同时提供有OLE功能。-Pad2 of a similar word-processing program, at the same time provide an OLE function.

ProgrammingPerl.pdf programming Perl is not jsut a book about Perl, it is also a unique introduction to the language and its culture, as one might expect only from its authors. This third edition has been expended to cover Version 5.6 of Perl.

用动态规划法-解决流水作业调度的问题,得出最优解-use dynamic programming-solving routine scheduling issues, and the optimal solution

可用于对指定的程序运行状态进行监控，如果退出运行或者已经没有响应（既死掉），则杀掉无响应的进程，并重新自动运行前保留现场屏幕到文件。-can be used for the specified procedures in the state are monitored, or if the decommissioning has not responded (both dead), then kill the process without a response, and automatic re-run the scene before the reservation screen of the document.

比较两个目录（包含子目录）并更新 1、发现目标目录缺少文件，则更新 2、发现目标目录的文件与源文件不同，则更新 3、更新时，保持与源目录结构相同-compare two directories (including subdirectories) and an update, the target directory lack of documentation, update 2, the target directory file with the source file were different, Update 3, update, and maintain the same source directory structure

高质量C++编程指导 一些编程规范和常见的容易犯错误的地方-High-quality C++ programming guide the number of programming norms and common areas prone to making mistakes

汇编程序shizhong -assembler shizhong

采用labview设计的和单片机通信,有一定参考价值-Design using LabVIEW ，coomn withMCU, has a certain reference value-Design using LabVIEW ，coomn with MCU, has a certain reference value

应用背景炫客无刷新聊天室，使用ASP + JS（阿贾克斯辅助）实现动态无刷新聊天室，个人版和站长版终身免费本程序完全免费，开源关键技术

这是一个典型的非数值问题，如果使用非递归算法求解此问题，要设计复杂的算法，编写很长的程序。而使用递归算法可以使整个算法清晰，使程序简洁。本问题分析并建立递归算法的过程是典型的抽取问题本质、建立递归算法 并最终解决非数值问题递归实例。-This is a typical non_numerical value problem.you must design complicated arithmetic and long program if you use non_recursion arithmetic.But if you make use of recursion arithmetic,your arithmetic will be clear.The course of analysing and establish recursion arithmetic is a typical example to take out the principle ,establish recursion arithmetic and solve non_numerical value problem.