Using java to develop horse line issue and realize the different ways in each ha...

各种解码译码电路模型的VerilogHDL描述-various decoder decoding circuit model of Verilog HDL description

一个功能不错的媒体播放器，许多朋友都需要的。看标题就知道了，非要凑满20字-A function of good media player, and many friends are needed. Look at the title will know, at least 20 characters insisted Cou

application the magic box AND a program to get the minimum and the maximum numbers of a set of numbers-application on the magic box AND a program to get the minimum and the maximum numbers of a set of numbers

rtp通信开源项目源码，适合任何平台，目前已经基本成熟。按照RFC3550实现,这使得它很容易地发送和接收RTP包和RTCP（RTP控制协议）.

authorware制作的隐藏菜单。是authorwarer的源程序。可用来做示范。-produced by the hidden menu. Yes authorwarer of the source. The model can be used to do.

USART-ATMEGA16A.rar是ATMEGA16的升级版本ATMEGA16A的串口的使用介绍，包括硬件设置和源代码-USART-ATMEGA16A.rar upgrade is the ATMEGA16 serial ATMEGA16A use, including hardware setup and source code

enabler－按钮激活工具-enabler- button activation tool

Firmware: U600XEHI2 Reassigning buttons. The archive 2 patch: 1) i_MainMenu Patch naznachet i button on main menu, and the retention of the button - the menu activated Bluetooth. 2) LSoft_Java Patch appoints the left soft menu Java-based applications (makes sense with the first) Author: ArSik Ported: - Valerik0887-Firmware: U600XEHI2 Reassigning buttons. The archive 2 patch: 1) i_MainMenu Patch naznachet i button on main menu, and the retention of the button- the menu activated Bluetooth. 2) LSoft_Java Patch appoints the left soft menu Java-based applications (makes sense with the first) Author: ArSik Ported:- Valerik0887

快速FFT变换,C语言的,比较好用,我没试过-Fast FFT transform, C language, comparative ease of use, I have not tried

设计四 拔河游戏机 1、 设计一个能进行拔河游戏的电路。 2、 电路使用15个(或9个)发光二极管，开机后只有中间一个发亮，此即拔河的中心点。 3、 游戏双方各持一个按钮，迅速地、不断地按动，产生脉冲，谁按得快，亮点就向谁的方向移动，每按一次，亮点移动一次。 4、 亮点移到任一方终端二极管时，这一方就获胜，此时双方按钮均无作用，输出保持，只有复位后才使亮点恢复到中心。 5、 用数码管显示获胜者的盘数。 教学提示: 1、 按钮信号即输入的脉冲信号，每按一次按钮都应能进行有效的计数。 2、 用可逆计数器的加、减计数输入端分别接受两路脉冲信号，可逆计数器原始输出状态为0000，经译码器输出，使中间一只二极管发亮。 3、 当计数器进行加法计数时，亮点向右移；进行减法计数时，亮点向左移。 4、 由一个控制电路指示谁胜谁负，当亮点移到任一方终端时，由控制电路产生一个信号，使计数器停止计数。 5、 将双方终端二极管“点亮”信号分别接两个计数器的“使能”端，当一方取胜时，相应的计数器进行一次计数，这样得到双方取胜次数的显示。 6、 设置一个“复位”按钮，使亮点回到中心，取胜计数器也要设置一个“复位”按钮，使之能清零。--design a tug-of-war game, can design a game of tug of war circuit. 2, circuit use 15 (or 9), light-emitting diodes, come only among a shiny, namely, the center of tug-of-war. 3, the game with a two button rapidly and continuously pressed, have a pulse, who by fast, Who bright spots on the move, every time, a bright spot in Mobile. 4, the party moved to highlight terminal diode, on the winning side, this time the two sides had no effect buttons, to maintain output, so after only bright