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这是一个hotil管理系统软件采用VB,也inspensiable帮助…
这是一个有VB所做的宾馆管理系统软件 是大学生不可缺少的帮助-this is a hotil management system sofeware using vb,also a inspensiable help for graduates.
- 2022-01-21 01:34:52下载
- 积分:1
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串口通信SPComm示例(XE5)
串口通信SPComm示例(XE5)
SPCOMM控制項在Delphi串口通信中的應用:
Spcomm串列投送控制項具有多線程的特性,接收和發送數據分别在兩個線程內完成,接收線程負責收到數據時觸發......
谋求Spcomm 串口控制項向下位機發送數據示例代碼
- 2022-07-20 06:02:33下载
- 积分:1
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测试文件显示你好
A test C file display Hello
- 2022-10-03 03:55:03下载
- 积分:1
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实现VC中的字母跳动。字体改变,颜色改变。
实现VC中的字母跳动。字体改变,颜色改变。-The achievement of beating the letters VC. Change fonts, colors change.
- 2023-05-17 04:45:03下载
- 积分:1
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bullets Loader unlimited source Jinshan drifter and tickets can Ollydbg know : c...
反恐精英1.5的子弹无限Loader的源代
用金山游侠和Ollydbg可以得知:
改目录“反恐精英cstrikedlls”下mp.dll文件以下值可使应的武器子弹无限
-bullets Loader unlimited source Jinshan drifter and tickets can Ollydbg know : change directory " Counter-Strike cstrike dlls" mp.dll documents under the following values can be the force for unlimited bullets
- 2023-02-19 11:15:04下载
- 积分:1
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拓扑排序算法和主函数,希望大家好好运用,如果有什么不懂可以联系我哦...
拓扑排序算法和主函数,希望大家好好运用,如果有什么不懂可以联系我哦-topological sorting algorithm and the main function, we make good use of hope that if there is any link I can understand Oh
- 2022-07-11 20:11:58下载
- 积分:1
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VISTA风格控件!全力打造 绝对经典 VISTA风格控件!全力打造 绝对经典...
VISTA风格控件!全力打造 绝对经典 VISTA风格控件!全力打造 绝对经典-VISTA style control! To create VISTA style controls the absolute classic! To create an absolute classic
- 2022-01-26 04:43:45下载
- 积分:1
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操作系统中的生产者和消费者模拟程序.用WINDOWS API 实现.有很详细的文档说明...
操作系统中的生产者和消费者模拟程序.用WINDOWS API 实现.有很详细的文档说明-operating system producers and consumers of simulation procedures. Using Windows API. Very detailed documentation Note
- 2023-02-07 21:45:03下载
- 积分:1
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用单链表实现名片管理,本例还将数据结构与对话框,文档试图有机结合起来,希望能给读者以更多启发....
用单链表实现名片管理,本例还将数据结构与对话框,文档试图有机结合起来,希望能给读者以更多启发.-achieve card management, the cases will dialog with the data structure, the document attempts to combine the organic, hoping to give readers more enlightening.
- 2022-03-15 07:59:56下载
- 积分:1
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本程序针对约瑟夫问题的描述:编号为12,……n的n个人按顺时针方向围成一圈,每人持有一个密码(正整数),一开始任选一个正整数作为报数上限值m,从第一个人开始按顺...
本程序针对约瑟夫问题的描述:编号为12,……n的n个人按顺时针方向围成一圈,每人持有一个密码(正整数),一开始任选一个正整数作为报数上限值m,从第一个人开始按顺序时针方向自1开始顺序报数,报道m时停止报数,报m的人处列将他的密码作为新的m值,从他在顺时针方向上的下一个人开始重新从1报数,如此下去,直至所有人全部出列为止。利用单向循环链表存储结构模拟此过程,按照出列的顺序印出各人的编号。
演示程序以用户和计算机的对话方式执行,即在计算机终端上显示“提示信息”下,用户输入循环人数n和每人的密码。-This procedure description specifically for Joseph problem: The serial number is 12, ... The n n individual surrounds the ready-made one circle according to the clockwise sense , each person holds (positive integer) a password, one positive integer beginning to assume a post of selections is upper limits ms numbering off, direction starts the hour hand beginning from the first people according to order from 1 numbering off in proper order , stop numbering off when reporting m, the person place column reporting m looks on his password as new m value , the individual begins to number off again from 1 , getting down like this from his time as soon as going ahead in clockwise sense, until proprietor all till leaving self s place in the ranks.
- 2022-10-13 13:15:03下载
- 积分:1