这是我课程设计时做的一个小游戏，编得不太好，请各位高手指教！...

在资料中加上关键字索引的位置Tag(0x08:带偏移量)-Add a keyword in the data location index Tag (0x08: with offset)

Shape-Changing Progress Control

VHDL硬件描述语言基础,非常好的一本书，有时间不妨看看！-VHDL hardware description language based, a very good book, time to take a look!

用visual c++做的一款一维条码生成器-Using visual c++ to make a code generator

（1）可选择不同的规则集（用普通文本文件存贮规则）。 （2）利用VC TreeCtrl控件显示分析得到的句法结构树。 （3）中间分析过程产生的所有边都输出到结果文件，便于跟踪分析的细节。 （4）分析过程中，检索规则集中的规则，查到一条满足条件的规则就停止，因而产生的不是全部分析结果，并且，规则的顺序也会对分析结果有影响（可比较两个规则文件，其中规则内容一样，但有两条规则的顺序不同，在分析 “学习/verb 文件/noun” 这样的例子时结果就不同： -(1) choice of different sets of rules (using ordinary text file storage rules). (2) VC TreeCtrl control analysis showed the syntactic structure of the tree. (3) Intermediate analysis of all the edges are exported to the outcome document, and facilitate the tracking analysis of the details. (4) analysis process, the rules focus on the search rules, found a meet conditions to stop the rules, which not all of the analysis results, and, rules of the order will also have an impact on results of the analysis (which can compare the two rules, which rules the same content, but there are two the sequence of the different rules, the analysis of "learning/verb documents/noun" Such examples on the different results :

阿萨德

an example for uninstaller

一个简单的画图实现软件，可能很简单，可是对于简单的学习还是不错的-Implementation of a simple drawing software, may be very simple, but easy to learn for the good or

这是在D3D中设计一个水面一样的波纹的设计，例如电影中的一些水面的效果-This is the same as D3D to design a corrugated surface design, such as film some of the effect of water

public class gedebahe { public static void main( String [] args) { for ( ) { int a=-1,b,c //b,c是分解出来的两个数 System.out.print("Please input a oushu:") //输入一个偶数 try { BufferedReader in = new BufferedReader(new InputStreamReader(System.in)) String inputLine = in.readLine() a = Integer.valueOf(inputLine).intValue() }catch (Exception exc) { System.out.println("Sorry,please input a number.") return } if (a%2!=0) { System.out.println("Sorry,please input a oushu.") return } for (b=1 b