图的深度优先算法，这个算法非常的实用，应该经常被用到

BFS、DFS、有向图、无向图中的各种算法的实现，可以自动生成图形。-BFS, DFS, to the map, no map to the realization of the algorithm can be automatically generated graphics.

任意长整数相加问题 任意输入两个任意长的整数进行相加 可以得出正确结果，-arbitrary sum of long integer problem indiscriminate importation of two arbitrarily long integer can be drawn together for the right result,

数据结构C++语言描述--应用标准模板库-Data Structures C++ language description- Application of Standard Template Library

how to use crystal report

一个商品销售系统-a sales system

酒店综合管理系统 酒店综合管理系统-Hotel Management System Hotel Management System

数据结构课程设计报告1-sergyrt hgrth

ADO 访问Access数据库-ADO Access database

哈夫曼树算法 根据给定的n个权值{w1,w2,……wn}，构造n棵只有根结点的二叉树，令起权值为wj 在森林中选取两棵根结点权值最小的树作左右子树，构造一棵新的二叉树，置新二叉树根结点权值为其左右子树根结点权值之和 在森林中删除这两棵树，同时将新得到的二叉树加入森林中 重复上述两步，直到只含一棵树为止，这棵树即哈夫曼树 -Huffman tree algorithm based on a given n-weights (w1, w2, ... ... wn), construct n trees only a root node of the tree, so that from the right value of wj in the forest root node to select two the right tree for the value of the smallest subtree around, a new binary tree structure, the right to buy a new tree root node value of its subtree root node around the right value in the forest and delete these two trees, At the same time, the new binary tree obtained by adding the forest to repeat the above two steps until a tree containing only the date, that is, Huffman tree tree

数据结构课程设计,表达式,用C语言实现,难度系数较高-data structure curriculum design, expression, using C language, the higher the coefficient of difficulty