介绍了unix网络编程技术

射频电路设计，大牛的著作，初入门者必看的设计资料-RF circuit design, the cow works, the early entry of design information are a must-see

想成为VC高手必看的书-want to be masters of the book Watchable

C语言精彩编程176例，c语言学习的好资料，每个例子都很经典!-C programming language wonderful 176 cases, c language learning good information, each of the examples are classic!

C#代码,注册表浏览器 主要是浏览注册表的键值.-C# Code, registry browser is browsing the registry keys.

Java学习个人意见和见解-Java learning personal views and opinions

一本比较好的介绍C++技术的书 希望可以给想学C++的人带来帮组-A relatively good introduction C++ Technical book can give hope, like the C++ Bring help group

这是一个有关SN74128器件的资料,是我从国外找到的,和大家分享一下.-SN74128 the device information, I find from abroad, and share with you.

在一个划分成网格的操场上，n个士兵散乱地站在网格点上。网格点由整数坐标(x,y)表示。士兵们可以沿网格边上、下、左、右移动一步，但在同一时刻任一网格点上只能有一名士兵。按照军官的命令，士兵们要整齐地列成一个水平队列，即排列成(x,y),(x+1,y),…,(x+n-1,y)。如何选择x 和y的值才能使士兵们以最少的总移动步数排成一列。 实验任务：计算使所有士兵排成一行需要的最少移动步数。-In a grid divided into the playground, n soldiers stood scattered on the grid points. Grid point by the integer coordinates (x, y) express. Soldiers along the edge of the grid, down, left and right moving step, but at the same time any one grid point has only one soldier. In accordance with the officer s command, the soldiers should be neatly列成level queue, that is arranged in (x, y), (x+ 1, y), ..., (x+ N-1, y). How to choose x and y values to make the soldiers with the minimum of the total moves one line up. Experimental tasks: the calculation so that all the soldiers lined up his required minimum moves.

非c程序员c++入门自学教程-c c entry self-tutorial

有关JAVA的电子书籍对入门者有所帮助。-electronic books to help beginners.