try again for this up 3 compress,compress final

编写一个求解Josephus问题的函数。用整数序列1, 2, 3, ……, n表示顺序围坐在圆桌周围的人。然后使用n = 9, s = 1, m = 5，以及n = 9, s = 1, m = 0，或者n = 9, s = 1, m = 10作为输入数据，检查你的程序的正 确性和健壮性。最后分析所完成算法的时间复杂度。定义JosephusCircle类，其中含完成初始化、报数出圈成 员函数、输出显示等方法。-Josephus write a problem solving function. With the sequence of integers 1, 2, 3, ... ..., n the order of sitting around the round table, said the people around. And then use n = 9, s = 1, m = 5, and n = 9, s = 1, m = 0, or n = 9, s = 1, m = 10 as input data, check the correctness of your program and robustness. Completed the final analysis, the algorithm" s time complexity. Definition JosephusCircle class, which included the completion of initialization, reported that the number of member functions of a circle, the output display and other methods.

用七段数码管显示分秒值，程序开始运行时，时间值为00-00，每隔一秒，时间值改变一次，从键盘上敲任意键，程序退出-with paragraph 107 of Digital Display Minutes value, operational procedures, time value of 00-00, every second, the time value of a change from nice arbitrary keys, exit procedures

显示甘特图的一个实例，很好的很好的很好的-show gannt

红楼梦人员关系查询工具-Dream of the Red Chamber staff relations Query Tool

ARM嵌入式WINCE实践教程,采用JXARM9-2410作为实验平台-ARM Embedded WINCE Practice Guide, using JXARM9-2410 as an experimental platform

COM控件注册程序，注册后可以使用VB中的com控件-COM control, registration process, after registration you can use the VB controls in the com

本代码使用vb 编写矩阵汉字的显示-use of the code prepared vb matrix display Chinese characters

用递归将整数转换为字符串的C++程序 通过求得整数每位数，再将其转为ASCII码,再调换每位顺序-using recursive integral to the conversion to a string obtained by C program every few Integer, and then converted to ASCII and then swap each sequence

C8051F06X单片机编程，Blinky模块-C8051F06X Microcontroller Programmer, Blinky Module

运行时类型识别演示-runtime type identification demo