十字链表(数据结构作业)

数据结构上机实习关于多项式的源程序！是我同学编的！-data structure for the attachment of polynomial source! Part of my classmates!

(1) 初始化。从终端读入字符集大小n，以及n个字符和n个权值，建立哈夫曼树，并将它存于文件hfmTree.txt中。 (2) 编码。利用已建好的哈夫曼树，对文件ToBeTra.txt中的正文进行编码，然后将结果存入文件CodeFil.txt中。 (3) 译码。利用已建好的哈夫曼树将文件CodeFile.txt中的代码进行译码，结果存入文件Textfile.txt中。 -Huffman encoder/decoder

员工培训管理系统。本系统要完成的主要功能是：1.进入系统钱需要身份验证，用户名，密码。输入争取后方可进入。2.管理员可以根据需要定义员工，工作以及部门信息。3.管理员可以定义课程、书籍、教授以及培训的资源信息。4.管理员可以保存员工的培训成绩及员工经过培训之后对该课程和领域的评价。5.依据不同的要求，可以在数据库中对信息进行查询和编辑。-Staff training management system. To complete the system are the main functions: 1. Necessary money into the system authentication, user name, password. Before it can enter into the fight. 2. The administrator can be the definition of necessary staff, as well as the information department. 3. The administrator can define the curriculum, books, professor of information and training resources. 4. The administrator can save the training of its staff after a score and staff training in the areas of curriculum and assessment. 5. In accordance with different requirements, you can on the information in the database query and editing.

VB图书管理系统，基于VB的图书管理系统的程序开发，只作参考-VB library management system, library management system based on the VB-program development, only for reference

这是一个 java 文件来连接到 MONGODB 数据库适合初学者。MongoDB 支持 Map Reduce 和分片为了获得最佳性能。MongoDB 用于大数据

labyrinth: you need to find the doable way to go to the destinaton.And then print out the path.-labyrinth: You need to find the doable way to go to the destinaton.And then print out the path.

栈的基本操作，有初始化，清空，添加，删除，判空等!-stack the basic operation, initialization, emptied, add, delete, subcontracting air!

1、 字符串由随机产生的1~16位的字母组成，然后用插入排序、冒泡排序、堆排序、快速排序、归并排序对字符串进行排序。-1, the string randomly generated by the 1 ~ 16 of the letters, and then use Insertion Sort, Bubble Sort, Heap Sort, Quick sort, merge sort to sort on the string.

一个能求图中任两顶点之间的最短距离的程序-seeking a map to the two vertices of the shortest distance between the procedures

建立快速傅利叶变换 C 语言源代码 17K-establish Fast Fourier Transform C language source code 24K