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Web 1.3 system for messy with everyone learning to use! ! !
凌乱1.3网站系统供大家一起学习使用-Web 1.3 system for messy with everyone learning to use! ! !
- 2022-02-14 11:38:25下载
- 积分:1
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用于数据预处理的多小波分解与重构程序.其中多小波是采用CL4平衡多小波,所以分解前的预处理是采用等值预滤波器.如果要用别的非平衡多小波,只需替换为相应的预滤波器...
用于数据预处理的多小波分解与重构程序.其中多小波是采用CL4平衡多小波,所以分解前的预处理是采用等值预滤波器.如果要用别的非平衡多小波,只需替换为相应的预滤波器即可.-for data pretreatment multiwavelet decomposition and reconstruction process. Multiwavelet which is the Panasonic balance multiwavelets Therefore, the pretreatment before decomposition is the equivalent pre-filter. If you want other non-equilibrium multiwavelets only replacement for the corresponding pre-filter may be.
- 2022-08-11 09:51:21下载
- 积分:1
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电子芯片规则检查语言,用于cadence
电子芯片规则检查语言,用于cadence-Electronic chip rule checking language, for the cadence
- 2022-03-23 16:23:47下载
- 积分:1
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himself wrote for the refuse removal, like it used to clean up the garbage prett...
自己写的垃圾清理器,喜欢的用吧,清理垃圾帧的不错-himself wrote for the refuse removal, like it used to clean up the garbage pretty good frame
- 2022-04-14 23:44:11下载
- 积分:1
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系统分析师,文档,大家来看看了,对学计算机有帮助的!
系统分析师,文档,大家来看看了,对学计算机有帮助的!-Systems analyst, documentation, read the U.S. point of view on the school computer help!
- 2022-10-07 19:10:03下载
- 积分:1
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本程序实现了IFFT以及和连续变换的对比,并对连续以及离散的OFDM系统的对比...
本程序实现了IFFT以及和连续变换的对比,并对连续以及离散的OFDM系统的对比-This procedure, as well as implementation of the IFFT transform and continuous comparison of continuous and discrete OFDM system comparison
- 2023-01-21 01:55:04下载
- 积分:1
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Although it is a small example, but it is basically a C polymorphism meaning! It...
虽然是一个小小的例子,却是基本上包括了C++多态的含义!是很好的学习材料-Although it is a small example, but it is basically a C polymorphism meaning! It is a good learning materials
- 2022-03-03 05:41:24下载
- 积分:1
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闹钟程序用C++语言实现的
用C语言实现的闹钟程序.rar- Alarm clock procedure realizes which with the C language
rar
- 2023-01-22 21:15:03下载
- 积分:1
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ISOIEC
ISOIEC-15444-12-2004 æ ‡å‡†-ISOIEC- 15444-12-2004 standard
- 2022-07-08 22:01:49下载
- 积分:1
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邮票问题:设一国家发行n种不同面值的邮票,并且每封信至多允许贴m张邮票,对于给定的m,n值,写一个算法求出从邮资1开始在增量为一的情况下可能获得的邮资值的最大连...
邮票问题:设一国家发行n种不同面值的邮票,并且每封信至多允许贴m张邮票,对于给定的m,n值,写一个算法求出从邮资1开始在增量为一的情况下可能获得的邮资值的最大连续区域以及获得这个区域的各种可能面值的集合。如,当 n=4,m=5,若有面值为(1,4,12,21)的四种邮票,则邮资最大的连续区域为1到71。还有其他面值的四种邮票可组成同样大小的区域吗-stamp issue : Let a national issue n different denominations of the stamps and letters each allow up to m stamp affixed, to the m, n, write an algorithm derived from a postage in an increment of the circumstances, may obtain a postage value of the maximum continuous access to this region and regional various denominations could assemble. For example, when n = 4, m = 5, if the values of (1,4,12,21) of the four stamps, postage largest regional consecutive 1-71. There are four other denominations of the stamps can be the same size as the composition of the region? ?
- 2022-02-24 19:12:53下载
- 积分:1